IS THIS A REACTIONLESS DRIVE OR A PERPETUAL MOTION MACHINE?

[George1]

Hi guys,
A friend from another OU forum gives an interesting idea. He suggests the zigzag rounded curves to be replaced with sharp zigzag forms similar to saw teeth.  In this case, he says, the possible violation-of-the-two-conservation-laws effect would be as if even much greater. What do you think about his suggestion?
Looking forward to your answer.
Regards,
George

[George1]

Any opinions related to the saw-teeth zigzag model suggested by the colleague from a similar to ours OU website? (Please have a look at our last post.) His suggestion seems to be interesting.
Looking forward to your answer.
Regards,
George
 

[George1]

Hi guys,
I am re-sending again our post of May 10, 2019, 10:14:09 AM. This post as if most clearly supports the validity of our basic concept.
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Please have a look again at the first post of ours in this topic. Let us make the following comparison. (We will repeat some parts of our previous posts.)
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1) Please have a look at Fig. 4, Fig. 5, Fig. 5A and Fig. 6.
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1A) THERE IS NO FRICTION. (Modern technologies allow to reduce practically as much as you want the experimental error, related to friction.)
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1B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the zigzag channel section the blue component will decelerate. And it is also evident that the deceleration d (its absolute value and its mean value) will be bigger than zero, that is, d > 0.
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1C) It is evident that if the blue component enters the zigzag channel section, then the black component exerts force Fc on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of Fc coincides with the direction of Vo. It is also evident that the force Fc (its absolute value and its mean value) is bigger than zero, that is, Fc > 0.
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2) Please have a look at Fig. 1, Fig. 2, Fig. 2A and Fig. 3.
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2A) THERE IS FRICTION in the linear channel s-segment section.
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2B) Let us assume that the black component is fixed motionless somewhere to some obstacle and is not able to move. In this case it is evident that after entering the linear channel s-segment section the blue component will decelerate. And it is also evident that the deceleration d' (its absolute value and its mean value) will be bigger than zero, that is, d' > 0.
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2C) It is evident that if the blue component enters the linear channel s-segment section, then the black component exerts force F'c on the obstacle, which does not allow the black component's linear motion. It is evident that the direction of F'c coincides with the direction of Vo. It is also evident that the force F'c (its absolute value and its mean value) is bigger than zero, that is, F'c > 0.
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3) Please compare item 1 with item 2. It is evident that we can always choose a suitable combination of (a) magnitude of force of friction, (b) length of segments s and (c) number and shape of zigzags, for which Fc = F'c, Fc > 0, F'c > 0, d = d', d > 0 and d' > 0. Therefore it is evident that zigzags successfully imitate resistance, which is identical to friction, but without generating heat. And if we use this simple fact in the experiments, described in Figs. 1 - 6, then we can conclude again that:
a) the law of conservation of linear momentum is not correct;
b) the law of conservation of mechanical energy is not correct;
c) both the law of conservation of linear momentum and the law of conservation of mechanical energy are not correct simultaneously.
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Let us stress upon the fact that IN GENERAL both the law of conservation of mechanical energy and the law of conservation of linear momentum are absolutely true and correct. There is no doubt about this. But any rule/law has its exceptions and there is nothing special, disturbing and tragic in this fact.
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Looking forward to your answer.
Regards,
George 

[tinu]

Please stop this crap already, will you? If you can't come with experimental results better stfu!
And stop spamming us again and again with your nonsense!
Can you understand this is a public forum or you're simply retard?

[George1]

tinu,
You did not take your medicine again this morning. I will talk to your doctor to forbid you to write in this forum and take away your computer. You are dangerous for you yourself and for the others.
May be you have to change the medicine? Because obviously the medicine you are taking is not effective enough.