The book is dedicated to self-propelled mechanical generating devices.

[rakarskiy]

A caring guy conducted a demonstration experiment for me with a simple generator. For which I am very grateful to him!

Video clip: https://www.youtube.com/watch?v=yOq1TN3lnIo

My updated theory is fully confirmed. My analysis is on the slide, if you can read the formulas, everything can be seen in the palm of your hand.

I have already been asked questions about the motor that I described in the article.  I will do a full analysis and methodology in the manual.

[rakarskiy]

I analyzed the experiment more deeply and found inaccuracies in determining the magnetic induction of a magnet in the wire area.
My method is very correct, I am very happy about it.
The magnetic induction of the magnet can be calculated on this page:

https://www.kjmagnetics.com/calculator.asp?calcType=block

PS: I haven't found anywhere else yet, a similar methodology for calculating the resulting ampere force

[bistander]

Looking for something like this?
bi

https://www.calctool.org/CALC/phys/electromagnetism/ampere_law

[rakarskiy]

In general, I corrected my calculations a little, and everything came closer to equilibrium. The coefficient for the resulting magnetic induction in the calculation of the ampere force must be calculated more simply k' =U' / E, where - U' is the dimension of the voltage drop U' = I*∑R the product of the current by the total resistance of the circuit, including the reactance (in electrical engineering, the inductive resistance x = L * f). As a result, everything converges to the point of correctness of the table data (up to 20 turns). If there were no reactance, then the electrical and mechanical power of the generator would be equal. 

https://www.youtube.com/watch?v=yOq1TN3lnIo&t=77s


Having studied and worked out the ampere power system, I immediately identified the engine option: two-phase. control of electric valves with compensation of the reactance of the circuit during switching.
I do not know what will come of it, but the calculation is still beneficial to the prospect.
*

http://rakarskiy.narod.ru/_pu/1/92585013.jpg

[rakarskiy]

Have a good time, friends!
Caring guy Rich, made a clarifying experiment for magnetic induction from a magnet in the area of the wire of his generator.

https://www.youtube.com/watch?v=VAM9TLfUDkQ&t=30s

Unfortunately, his measurements are inaccurate. The reason is its data on the current strength, the resistance of the circuit with the load, the voltage at the terminals of the generator at 15 turns.
These data are sufficient to calculate the magnetic induction from the magnetic pole in the area of the generator winding wire.

To find out the voltage drop during current induction, it is enough to multiply the resistance of the circuit by the current strength in the circuit:  U'=R*Ig = 4 Ohm * 1.3 A = 5.4 V
Next, the voltage at the terminals of the generator connected to the load is added to the drop voltage and we get the EMF of the generator:  E = U'+Ug = 5.4 + 10.4 = 15.6 V
The rate of change of magnetic induction is determined by this formula: v = π*r*rpm/30  it will be: 11,52 m / s.
The length of one coil of the active wire is 0.66 meters * 15 turns: L = 9.90 meters

Now we are from the EMF formula [E = Bm*L*v]  we can find magnetic induction: Bm = E/v/L  = 15.6V / 9.9 m / 11.52 m/s  =  0.1369 T  [As you can see, its value is not equal to 0.082 T].

you can use a calculator to calculate the magnetic induction and force for a magnet at a distance: https://www.kjmagnetics.com/calculator.asp?calcType=block

Next, to determine the resulting ampere force, you need to calculate the resulting magnetic induction, for this I recommend using my method of multiplying the resulting magnetic induction by the voltage drop coefficient:  k' = Ug/E  =  10.4 / 15.6 = 0.67   
If you want, call this coefficient - the Rakarsky coefficient, but it will not change the essence.

Next, we find the value of the resulting magnetic induction from the value of the magnetic induction of the magnet:  B = Bm * k'  =   0.1369 T  * 0.67  =  0.091 T.

Next, we find the ampere force and the electromagnetic moment, which is 0.065 N * m (yellow row of the table)

If we take the electrical power of the generator under load: 10.4 V * 1.3 A = 13.52 W, we can calculate its electromagnetic moment by the formula: Mg=Рg*9,55/rpm   = 13,52*9,55/2000 = 0,065 Nm.

The electrical and mechanical power of the generator are equal, the problem is solved.

Rich, thank you for the experiments, write me an email.