Inarticulate minds stuck in convolution

[Mr.Miyagi]

I=U/R. To measure U by knowing R is to measure I. It's painful to have to explain this kind of basic beginner stuff. Until you have taught yourself "U=RI", there is no point in giving lessons from the top of your ignorance.

A 10 ohm resistor at 2 MHz, that of which you have no "precision" of, especially if it is wire wound, which is highly likely, could have an Impedance of 10 KOhms for all you know!

Ok, I cant resist the urge of subsumption.

Hi Void

Yes,turns out these !so called! non inductive resisters become quite inductive after 2MHz-ok below that.

Swapping it out for a 1/2 watt carbon resistor made all the magical OU disappear 


Brad

If I were you, F6FLT, I would have a little break, look for something yoU are good at!

[Mr.Miyagi]

Oh my 

The truth is-some one has forgotten to take there med's today.

I am sad for you, not for me!

Do you know what the result of all this will be?

[tinman]

Do you know what the result of all this will be?

Yes
Your book is going to be an epic fail.

Now,you state that i never measured the output power--that phase angle was not taken into account,and that the scope dose not account for phase angle.
So can you please explain to all of us how you go about measuring dissipated power of a load resistor ?


Brad

[Mr.Miyagi]

Yes
Your book is going to be an epic fail.

Now,you state that i never measured the output power--that phase angle was not taken into account,and that the scope dose not account for phase angle.
So can you please explain to all of us how you go about measuring dissipated power of a load resistor ?


Brad

Your games are on going. As are your lies!

The.Truth is, I was right and you dont like it.

I have nothing to prove to you, or anyone as a matter of fact.

I really would like to see some of you, a little more with your brains and a little less with your mouths. But thats got nothing to do with me. Your path is yours.

BTW - Made any dollars yet from anything other than your Day Job?

[Mr.Miyagi]

Yes
Your book is going to be an epic fail.

Now,you state that i never measured the output power--that phase angle was not taken into account,and that the scope dose not account for phase angle.
So can you please explain to all of us how you go about measuring dissipated power of a load resistor ?


Brad

Also, I wish to point out, as: F6FLT just found out, Ohms Law can ONLY be used, if at least two of the quantity's are known and guaranteed to be correct. Clearly your Resistance value was not.

An accurate measurement of the current in the secondary circuit as I pointed out would have reveled that as I pointed out.

Why was your Resistance value not valid?