Getting energy from asymmetry of the magnetic field experiment

[ayeaye]

Maybe i was not clear enough about friction.

When an object moves by whatever force, the force of friction is always against the force that makes the object to move. That is, on dry slippery smooth surfaces when the object stands, the friction force is equal to the summary force to the object, until that summary force increases the maximum friction force. Then the object starts to move, and the friction force remains the same. When talking about the friction force below here, we mean that maximum friction force at the particular location. Friction force is an electromagnetic force between molecules or atoms of two surfaces against each other.

Thus, when we put the magnet somewhere and measure the force, the measured force is likely the real force to the magnet minus friction. Because the force to be measured, requires a slight movement towards the measured force, even if the movement is very slight. For any such movement, the force to the magnet must overcome the friction force. And the friction force does not disappear when the movement ends and the magnet stands still.

At any point, we can measure two forces. One is just before the magnet starts to move in the direction where we pull, this is the real force plus friction. The other is just before the magnet starts to move in the direction opposite to where we pull. This is the real force minus friction. Because for any movement to happen, the difference between the force to the magnet and the pulling force, must be greater than the friction force.

The real force is the average of these two forces. And the friction force is difference between these two forces, divided by two.

Also as i said before, adding the energies does not increase the error. This is because the scales don't always err to one side. The error is thus the difference between the greatest energy (of the energies added) calculated with the measured force plus the error of the scales, and the same energy calculated with the measured force minus the error of the scales.

Approximately, to convert kg to Newtons, multiply with 9.8, to convert kg * cm to milli Joules, multiply with 98. Like you had 37 milli Joules at the left side, and 29 milli Joules at the right side.

[telecom]

I notice that your small moving magnet is rather wide, i used a much narrower small magnet. I'm not sure whether it's true, but how i see it by now, any irregularity of the field there may be, a wide moving magnet may make it all more even, something. If you have only one kind of magnets, these with poles on the wider sides, if you have them too many, and if they are ceramic magnets, maybe split some to half in the middle, sorry to recommend that... What i can say by now.

Good point, the easiest probably would be just getting a small magnet somewhere. I will work on it.

[telecom]

done some more measurements w the same setup:
this time my friend was holding a plastic ruler on top to prevent it from jumping out.
left:
.24, 0.6, .30,.20
right:
.36, .08, .10, 0
reading taken each centimeter

[telecom]

Then I placed stack of the magnets horizontal, out of curiocity

[telecom]

The readings Re like that:
left:
.20, .16, .14, .32, .10

right:
.20, .08, .32, .16, 0

at the end of right travel there is a very strong vertical attraction force, will try measuring as well. which equals .30 kg
and at the end of the left travel there is a very big repelling force more than .4

all the readings are in kg