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Overunity Machines Forum



Капанадзе

Started by justawatt, October 20, 2020, 03:25:53 PM

Previous topic - Next topic

0 Members and 11 Guests are viewing this topic.

NickZ

Quote from: r2fpl on October 27, 2020, 12:37:57 PM
FE is closer to you than you think. I have done FE many times to see that it exists, possibly you did it too just didn't understand it. Everyone has it before their eyes. Let me say more, you think that's not it! I have been dealing with the subject for several years to understand what I saw in the first year.
It is so trivial that I'm afraid if I told you you wouldn't be taking me seriously. That's why I prefer to wait. I know you are nervous because time passes and nobody wants to say anything.

   r2fpl:
   If it's so trivial, it's not self running, nor even OU. As that is not trivial.
   Sorry r2fpl, but I don't believe that you have FE, nor OU, nor have ever seen anything self running. Please show us. Don't just expect us to just believe you. As there is not a single person on this forum that has what you say that you have, or claim to have seen. And therefore my doubts about your statements. And so, you're right, I don't take you seriously.   It's not that I'm "nervous", but I am leary of these unsubstantiated claims. As we've heard them all before.   IF you have nothing to show, then don't expect anyone to believe you, when you say what you just said. Even though you may be a nice guy, and I do appreciate your positive attitude.
   
   NickZ

pix



Imagine huge potential difference between Tesla coil top and ground.

Electrons are "sucked" from the ground. It is resonant amplifier that collects energy during every swing. With every push from primary more inertia is building up in secondary, as voltage is rising on Tesla coil top, and current is rising at the ground node. Frequency of pendulum oscillations do not depends from the mass of pendulum.
It is like during every push for mechanical pendulum, mass of the oscillating weight is increasing. You started with, let's say 0,1 kg mass on pendulum, and after some time the swinging mass has 1 kg. Energy is collected in the swinging pendulum, but frequency (resonant) is the same.
Do you see now?



Quote from: NickZ on October 27, 2020, 10:14:51 AM
   V8Karlo:   I would if I could. But, I don't see any free electrons, nor free energy of any kind by the use of a Tesla coil/Kacher circuit, by itself.   Nor have I seen a Kacher self running. Which makes me wonder why after all these years, if they are the source of free electrons.   We have been using the reverse windings on the HV Kacher's balun, and also on the grenade coils, for years. Nothing to show for it, so far.   I have a feeling that we'll see this device go the same route as the Roma (Poma) device. As no one can get it working right.   So guys, call Bunk, and get some help with this. Or don't, it's up to you.
But, that's what I would do. Maybe go and meet with him, if possible. Or watch this device fade out, like all the others have.

    NickZ

r2fpl

pix , NickZ


That's why I wrote that you see it and do not understand. What PIX wrote is your FE. Now why can't you have it? Because we don't know the method of receiving this energy. Kapanadze found a way to pick it up, but it's more of a method of connecting current than receiving. Interoperability is also possible. Here it is helpful to understand how the electron works and why the voltage and current are increasing or not.

Nick: did you understand how the Tesla Coil works? and what it gives us. And most importantly where the energy comes from.
I have 100% proof that the FE is there because I did tests that there is voltage and current! All you need is an oscilloscope and a current probe that you surely have.

Another important point is how to start the Tesla coil inductor. If you are using the kacher it is obvious you have never seen FE.
If you want, I can tell you what you have to do to see FE. Maybe the group on Skype we will create will be helpful?

pix


@r2fpl
The simplest way to extract energy from Tesla without disturbing resonance is by spark from top terminal. Tariel Kapanadze used it in Turkey demonstration. Movies are on YT. Spark from Tesla top goes to the ground by HV step down air transformer.
Driving Tesla coil- like Tesla said: loose coupling between primary and secondary at the  node ("ground")level, where  the current is.
To make coupling even looser, an extra "third" coil was used.


Quote from: r2fpl on October 28, 2020, 03:43:00 AM
pix , NickZ


That's why I wrote that you see it and do not understand. What PIX wrote is your FE. Now why can't you have it? Because we don't know the method of receiving this energy. Kapanadze found a way to pick it up, but it's more of a method of connecting current than receiving. Interoperability is also possible. Here it is helpful to understand how the electron works and why the voltage and current are increasing or not.

Nick: did you understand how the Tesla Coil works? and what it gives us. And most importantly where the energy comes from.
I have 100% proof that the FE is there because I did tests that there is voltage and current! All you need is an oscilloscope and a current probe that you surely have.

Another important point is how to start the Tesla coil inductor. If you are using the kacher it is obvious you have never seen FE.
If you want, I can tell you what you have to do to see FE. Maybe the group on Skype we will create will be helpful?

Jeg

Quote from: Void on October 27, 2020, 02:04:45 PM
Hi Jeg.  Not sure about the open circuit/unloaded voltage, but amplifiers like that may have problems if you don't have a load connected,
due to the reflected power back to the transistors. You could blow the output transisitors, if the amplifier doesn't have protection circuitry.

For a 50 ohm resistive load:
If you take the peak output power of that amplifier as 200W (when amplifying a complex waveform, like for AM/FM)),
and use a resistive load of 50 ohms (equipment for ham radio use is typically designed to work into a 50 ohm load),
then you would have:
P = V^2/R  (assuming a purely resistive load)
200 = V^2 / 50
10000 = V^2
V = sqrt(10000)
V = 100V RMS (when driving a 50 ohm resistive load, and assuming a sinewave)

If you can run 400W into a 50 ohm resistive load (that little HF amplifier will probably overheat),
then the output voltage on a 50 ohm resistive load would be: 141.42V RMS.


Hi Void
Thanks a lot for your answer. May i ask one more question. Does this 50 ohm load resistor, also contains the reactance of the load or is it just the ohmic part?