Mechanical resonant oscillation as basic overunity method

[Willy]

Very well then sir, shall we continue on, toward and through #2 ?

#2. I willy say that "there is no energy gain here."

As before we both agree to ...

That in order to eliminate all confusion, YOU must first describe HERE IN, for me, the conditions
under which I have claimed "there is no energy gain here".

[sm0ky2]

analyze the power input to each of the examples
include the energy required to reach resonance speed.


Add the energy input every cycle (at resonance)


Compare these added totals to the amount of fluid pumped.


results prove that a flywheel is more efficient than any of the examples.

[perpetual]

Ok, let's say conditions are a 10 meter tall tube half meter wide, obviously fully filled with water above a water pool wide enough to support such large column of water.

We got a steel spindle, elongated, sharp pointed, water resistance minimized.

Spindle has 10kg but due to air chamber inside it has -10kg in water.

Spindle is inserted at the bottom of the tube and let go.

Over a pully -10kg weighing spindle is spinning - for the sake of argument - 100% efficient generator and all energy - the tiny losses due to water resistance is captured in the capacitors or batteries.

As spindle hits the top small valve is opened on it, it releases the air out, now it weighs 10kg and free falls back to the bottom again spinning the generator and all the energy is again captured.

Once back at the bottom pump is pumping the air released at the top through a small tube running vertically through the whole big tube back into the spindle.

Cycle repeats.

Question, what is the energy needed to pump the air back down into spindle.

First and logical assumption would be energy equal to energy needed to lift the displaced weight of water (10kg) to that height (10m).

And energy to lift 10kg to that height is equal to energy spindle generated IN ONE DIRECTION, whether falling up or down, two being exactly the same.

Thus, energy produced in one direction is completely free and efficiency of the system is around 200%.

Additional info. It is possible altho not very likely that energy needed to pump the air back down is even less due to the fact this is not exactly the same situation as when suction is created from above the tube. Here, pumping is done from the bottom through the tube going up. It is clearly seen in video below he fills this big tube with few breaths and it appears effortless.

https://youtu.be/6RnorkCkEqI?t=59

Of course this is far far from a 10m tube.

It is hard to be sure if energy needed to pump the air back down is less than spindle generates as it falls up or down, but it is definitely not more.

Nix

[sm0ky2]

Want to measure the vacuum force inside this 'sealed, partially submerged' tube?
It is equal to the force required to hold that tube above the waterline.

[Willy]

Want to measure the vacuum force inside this 'sealed, partially submerged' tube?
It is equal to the force required to hold that tube above the waterline.

Agree

Given that for the sake of the discussion, we assign a value to the EMPTY tube as having
neither weight nor buoyancy in either atmosphere or water.

word EMPTY was late edited in for clarity... willy