Igors switcher (EMF recycler2)

[pese]

@ drspark

also in message #51
the inverter circuit is wrong designed and can not work.

if sombody need to know, why ... ask on message or email
pese

[wizkycho]

...we are getting closer, what a nice progress - even if it is "only" a math simmulation...
Now look at the picture bellow... at first it doesn't seem much... Oo but think more than twice.
E Output rises by one unit (+1)... we've been ignoring other points of E extraction in our circuit, till now. This change will just make higher output, leaving input as it is.

disadvantage: little more complex switching.

wiz

[hartiberlin]

@DrSpark,
if you use normal standard Iron cores for the transformer,
you can only use frequencies up to about 70 Hz,
otherwise your hysteresis losses will be too high.
If you want to go to 1.5 Khz you should then use a ferrite transformer.

@Pese.
where are the exact errors in the sims ?
I guess, if the sims show some excess, then
it is indeed something there, if he did setup the simulations
right with all the start parameters !

@Igor,
thanks for your new graphics, but it is hard to understand.
What do you want exactly to change now ?
Can you please explain some more ?

Many thanks.

Regards, Stefan.

[pese]

@stefan,
ich reklamiere nur , das trafo in #43 mit elkos AC m?ssig jurzgeschlossen ist und somit BALLAST (load) darstellen.
C4,C/+C8 sind an Pin 2+3 des prim?rkreises angeschlossen.
Beide C gegen Ground.  Das ist derselbe "Kurzschluss" als w?rde man
einen Kondensator an 4+5 des sekund?rkreises h?ngen. Der Ballast
durch den Kondensator (f?r AC) ist so gross dass diese Stufe SO
nicht arbeiten kann . Sorry , diese theoretischen Dinge sind f?r mich schwierig in englisch auszudr?cken . G.Pese

Die Inverterschaltung (#51) hat auch "dicke" Fehler . SO ,nicht nachbauen!

[wizkycho]

@Igor,
thanks for your new graphics, but it is hard to understand.
What do you want exactly to change now ?
Can you please explain some more ?

Many thanks.

Regards, Stefan.

... to cut the story, I made a mistake. I expected for a moment that R2 would behave like a aditional voltage rise...well it is but with reverse polarity for R2 so If R2 is in circuit (R2=R1) voltage on R1 drops to half of what it was without using R2 so Ecase1=Ecase2...
I desperatly wanted to save some more charges...maybe there is another way...

igor