Free energy from gravitation using Newtonian Physic

[supersam]

@ all,

i think i know for sure what is cleared up.  the fact that pequaide has the ability to post a video of his experiment!

lol
sam

[pequaide]

P-Motion Please be more specific as to what you think doesn?t work; I thought everything works just fine.

Both the last two pictures are of the same cylinder and spheres devices in freefall. It was spun by hand and released when the spheres were seated in the holes. The spheres unwind and swing out on the end of the strings, when they swing out the cylinder stops after about a quarter turn. The string is seen on both sides of the slit showing that the cylinder is not moving and that the spheres are. Video tapes can break it down into 1/30 of a second, the cylinder stops.

The mass of this particular cylinder is about 630g; the spheres have a mass of 67g each. 630+134 = 764, 764/134 = 5.7. This would be like 5.7 kg being stopped by transferring the motion to 1 kg.

[pequaide]

P-Motion: You asked if it is overunity.   

Answer; You start with 1 kg at .5 m elevation and end with 1 kg at 1.5 m elevation. I assume that this is one definition of overunity.

P-Motion:  What I wonder about is the ability of the spheres to transfer force to the cylinder or the other sphere.

Answer: The strings have tension in them, which means force is in the string, Newton?s Third Law states that the force in the string will be equal in both directions, and the Second Law states that the momentum change will be equal on both ends of the string.

P-Motion:  It seems the set up transfers force/potential from the cylinder to the spheres.

Answer: The setup transfers momentum from the cylinder to the spheres.

P-Motion:  For the spheres to be able to effect each other, they would have to be on an arm attached to the cylinder.

Answer: Are we concerned if the spheres affect each other. The spheres remove momentum from the cylinder, I am unconcerned if they affect each other. 

P-Motion:  And the cylinder would have to be designed to allow for spin/velocity to be increased by gravity.

Answer: The vertical overbalance wheel is ?designed to allow for spin/velocity to be increased by gravity?. The cylinder and spheres portion is mounted horizontally and is unaffected by gravity.

P-Motion:  In other words, it would have to allow for linear momentum to be converted to angular momentum.

Answer: Motion changes from linear to circular easily; often; and is 100% efficient in both directions.

P-Motion:  But with the 2 spheres being attached by a string, the spin necessary for the cylinder to create enough inertia would be high.

Answer: Inertia occurs in the lowest degrees of slowness. When released the spheres attempt to maintain a straight line motion, whether they are moving slow or fast. The cylinder pulls the spheres from this straight line motion and the force in the string begins to increase, at any velocity.

P-Motion:  Since any overunity design is dependent upon 9.8m/s/s, and with a changing of the mechanics of a device, its' spin will be limited.

Answer: The momentum transfer of the cylinder and spheres device is not limited by any spin rate that I know of. The effect is the same; slow or fast. The overbalanced wheel portion is of course limited by the acceleration caused by gravity.

[Kator01]

Hello all,

I wonder if anybody has looked to my post #110, page 8, because I try to find analogies of impuls-transfer either in nature or  in man-made system we are not aware of.

P-Motion, I also like this thread because it is a challenge to figure out a way to transfer impuls in a way nature does not show us - or should I say scientific or technical education we went through has been conducted in a tunnel-view manner.

I looked at the pendulums ( animation I was posting in my reply #110, and to the formulas again and again. I asked myself why the heck is the conservation-process of momentum-transfer from two 1kg-  masses hitting a single 1kg - mass happening only in a manner focussed on the target-mass and not
on the velocity ? More clearly expressed : Why does the process not solely increase the velocity of the one kg-mass and stop the 2 kg masses in order to fullfill the equilibrium in this equation p = 2 kg * V1 = 1kg * 2*v1 ?

The answer is of course : intertia of masses prevail. The inertia of a 1kg mass cannot stop a 2 kg-mass.

I have not yet figure out how to technically do this besides what pequaide has presented here. I only have grasped this one idea of spin-inertia because here spin-inertia of a 2 kg mass on a wheel can be made equal in value by placing the reaction-partner-mass of 1kg on a wheel with double the radius of the two kg-mass-wheel. Now both systems having the same spin-intertia might provide a chance that  velocity of target mass is increased in a way the 2 kg mass is stopped.

Maybe that you all here have already mentally worked this trough. I myself concentrate on different way to do this momentum-transfer.

I hope I have been able to bring across my point here. As an enginneer in applies car-construction I have learned  tunnel-view realities and I always was struggeling to overcome this.

Another idea came to my mind : a flowing water-mass beeing stopped suddenly by a valve - a technique which is state of the art since almost 200 years - by name of
hydraulic ram pump

principle : Water-hammer-shock-wave

have a look here

http://virtual.clemson.edu/groups/irrig/Equip/ram.htm

Can this technique be changed so it fits in in this momentum-transfer-problem ?

The hydraulic-ramp-pump-principe increases pressure in a tank.Gas is compressible, water is almost incomressible and thus suitable for the elastical-bounce-case.   
This pump does not transfer the momentum of a very long slow moving water-column beeing stopped->  to a small water-mass at high velocity.

What do you think ?

Best wishes for year 2008

Kator

[Kator01]

Hello P-Motion,

I have a few questions. I simply do miss some steps in your description.

- two weights : weigth at left is in fiixed position ? I assume both masses are of the same weight.
- why does the center of the rotating arm has two positions ? Is the center ( axis ) not fixed ?
    Does it wobble ?

I simply do not understand the whole process because I do not understand the basic setup especially this :

In the schematic, when the arm has rotated to the desired angle, if the over balanced weight changes its' course, it can return to a balanced position.

- ... What is the desired angle and at which step in the process ?
- ... Changes its course at what position or angle ?
- ... It can return to a balanced position at what angle ?

Can you please give me a more specific description if you have the time ?

Kator