new magnetic motor goes 2000 rpm without load 1000 rpm with load

[hartiberlin]

we have the battery charged its taking 2 amps continus

the 5 amps we pulled was on the pump

So that means, although you drive a pump with 5 amps from the same battery
and you also power the motor for the drive device,
the ampmeter shows -(minus) 2 amps directly at the pluspole of the battery,
so indeed the battery is recharged all the time by the device
and additionally operating the pump and the motor ?

Is this correct ?

Regards, Stefan.

[magnacoaster]

ok i think you all are not seeing it

i get 2 amps out to the battery (it keeps it toped)
i ran a air pump and it showed no discharge from the battery
it bulled about 5 amps i put it in front of the meter that was hooked to the battery


so no there was no use of the battery just a recharge
i also found a place to wind my new coils they have a winder
and figure it can make 12 within a hour this way they will all be
the same size and thickness

as well i have made a new drive wheel i went looking for a
electronic sensor but have not found one that will do
50,000 opens a minute

[wattsup]

@MC

I think what hartiberlin really wants to know is what we all want to know, and the information you are suppying is non-conclusive of anything (to us) until it is clearly understood.

Example, when giving voltages, you never really have 12 volts, it's always 12 point something. A battery is rarely at 12 on the dot. Also, amperage at 2, it never really 2 but 2.XX. Also, the air pump is at 12 volts and not 12.XX and the amps is never 5 but 5.XX. Unless the 12v 5A is what is written on the pump label as its rated voltage and amperage. So if the air pump is not loaded or not pumping anything, the pump is not drawing 5 amps, but mostly 1 or 2. The amps rating is under load and under load, air pumps will draw current and warm up  like anything else.

So from what I am understanding, you are running an air pump, maybe unloaded and it is drawing 1 or 2 amps (maybe not 5), and the generator is devellopping 2 amps. So the gain/loss potential is very small and with a 12 volt car battery, it could take a long time for the battery to lower in voltage if it is in a small loss situation.

Lastly, you are not mentioning the current draw from your two coil drive motor section
or if the battery is running this also.

Sorry to be such a pain or sound negative but all I am trying to do is give you an understanding of what it takes to show people exactly what is happening with your device in a concrete manner so as not to create any possibility of misunderstandings. regardless of where you wisht o show your device, the better you convey your comments and results, the less time you will spend trying to explain yourself afterwards.

I have made a small diagram to show you what I mean. If your set-up is similiar or close, you can do as follows,

1) Set the air pump pressure using an outlet valve so that is will not fluctuate while you take your readings.
2) Take amperage readings at A, B, C and D.
3) Take voltage readings at V1, V2 and V3.

This should be enough to calculate any OU potential. Now if the calculation winds up that the gain or loss is so small. Then it would have to be run for X hours to confirm.

All the best and good work.

[kallstrom_74]

any news on this thing??

[magnacoaster]

well i tore it all apart and made it from scratch its all made from nylon as well as a new genorator head and bigger magnets i just have to get it all back togeather on the weekend so i can see what the output will be