Chas Campbell free power motor

[hartiberlin]

Here it is once again with a better picture:

On the left side:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then:

1 ball at 3.9 distance from the axis x 1 Kg= 3.9 units
====================================
sum= 3.9 units


We still have a 3.9 versus 3.6 advantage.

Nobody has pointed out yet the error.
Yes, and I have about 30 degrees of rotation I can use ,
when I build it right for the red ball to go down,when I have an upper and lower flat rail,
not just 26 degrees !
As the yellow ball comes up it still has speed, so it can roll forward on a flat low friction rail
with no negative incline,
so you have almost 29 to 30 degrees for propulsion of the wheel there
and still the 3.9 to 3.6 advantage, so you could lift up the next yellow ball
and have again the same picture as below and the cycle begins again...

[hansvonlieven]

Zero,

You have just added 3 ft of additional energy into the system. Of course it will imbalance if you add additional energy.

Hans von Lieven

[Humbugger]

The ball is on the wheel for only 27.7 degrees out of 30

27.7/30 = 3.6/3.9

If you wish to quibble about the rounding errors, please do so on both sides of the equation.  By yourself.

Humbugger

[hartiberlin]

The ball is on the wheel for only 27.7 degrees out of 30

27.7/30 = 3.6/3.9

I can do better !
29 degrees!
What now

Why is nobody doing the torque calculations ?

[Humbugger]

The ball is on the wheel for only 27.7 degrees out of 30

27.7/30 = 3.6/3.9

I can do better !
29 degrees!
What now


Why is nobody doing the torque calculations ?

Since we are making up numbers arbitrarily, I bid 23