Over Unity NOT Achieved!!!

[lancaIV]

Read the Imris-publications, the relationship of induction/impedance/capacitance
under condensator use conditions ! Ohms law,partially neutralisized .
Less Ohm influence = less Kirchhoff influence ?

S
dL 

[oouthere]

I did not have any resistors powerful enough so I did the next best thing and used a bulb's measurements from the wall:

100 watt bulb at the wall:

.84 amps @ 120VAC = 143 ohms



Same bulb in the alternator:


(measured only across the bulb is 245VAC) .35 amps @ 142.85 ohms = TRUE 50VAC

The bulb was barely lit, equal to perhaps a 2.5 watt night light.

So, imo only 20% of the actual voltage is current producing and the other 80% is simply static voltage baffling people.

Rich

[oouthere]

I took a few pictures of my messy set-up but due to house renovations I can't find my camera transfer cable.  I also got a picture of the o'scope readings....nice sine waves.  I'll post a few when I find the cable.

Rich

[oouthere]

In order to save others heatache, disappointment, money and time, I'll run a leverage arm set-up using a known weight and rod length.  This will take the electronic mismeasurements out of the equation.  This will be done using my most effecient motor (5hp Baldor).  I don't know when I'll be completed though.

Rich

[hartiberlin]

Hi Rich,
if you run your 100 Watt light bulb from the grid wall, then you have 143 Ohms resistance, when the filament is hot glowing.
But when the filament is cold and not yet glowing, you might only have a resistance of 10 Ohms. So better use real resistors to measure the voltage across them.
It will be much more easier to buy a few high power ratings 10 Ohm resistors and use them instead of trying a prony brake setup I guess. If you have a real sinewave at the resistors, power can be calculated very easily and you could feel it, cause they are getting warm. No need for cos phi then at the static load resistor....