Stanley Meyer replication with low input power

[RunningBare]

I am actually still trying to get more information on the Tesla bifilar coil, my own experments have shown some interesting results when parallel fed, also if you tie one output to the input of the other then feed as shown.

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input
----cccccc-----|
               |
|--------------|
|
|-----cccccc----   
                  output


You get a much greater BEMF than that from a simular singular would coil with the same number of turns.
eg 50 turns each winding on the bifilar, 100 turns on the singular wound coil, the only way I can think that would happen is if the magnetic field potential is greater in the bifilar.

[RunningBare]

For the life of me I do not know why I went along with this resonating of tubes thing, I guess I got caught up in the excitement 

I believe very strongly that Meyers was NOT looking at the physical resonance of the tubes but in fact was looking at the resonance of a series resonant circuit, eg a coils and capacitors in series!, in this case the tubes would be the capacitor in question!, physical resonance when submerged in water would be so dampened down as to be unimportant.

If you can find the value of your inductors and the capacitance of your tubes then you can work out the resonant frequency, to find the resonant frequency is...

F=1/(2Pi(SQRT(LC))

In laymans terms, thats F = 1 divided by (2 x Pi x SQRT(L x C)), calculate the inner parenthasis first L x C, then get the square root of this, then multiply by 6.283(eg 2 x Pi) then do a 1 over, on your calculator it should look like [1/x]

Where F=resonant frequency, L=inductance of coil, C=capacitance of tubes.

A good LC bridge meter should be able to read the capacitance of the tubes while they are submerged in the water.

Once you have that frequency, try tuning the high frequency pulse to it.

[RunningBare]

I've had this discussion a number of times, if the wires were bare side by side touching then the magnetic potential would be shorted out, in effect it might as well only be one winding, by keeping the windings seperate they reinforce the magnetic potential in each other.

If they can touch, and they can, they can just as well be a single wire.  If the surface area is the same and the cross section is the same, there would be no difference even counting skin effect. 

Hissyfit

[Gustav22]

I'm trying to build onto an idea posted by tao et al. regarding the speed of sound in water and related calculations.

If you have a set of tuning forks, consisting of one fork tuned to a tone such as C flat
and several others forks tuned to 1, 2, 3 ... octaves above and/or below, all of them will resonate if only one of them is struck.

Example: If the frequency of the biggest  fork is per chance 2675 Hz
the frequency of the next smaller fork would be 5350 Hz to be one octave higher and
the frequency of the next smaller one would be 10700 Hz and
the frequency of the next smaller one would be 21400 Hz and
the frequency of the next smaller one would be 42800 Hz and
so on.

That's like always doubling the frequency, such as:
1 (basic frequency)
2 (one ocatve up)
4 (next octave)
8 (next octave)
16
32, 64, 128, ...

...... concentric cylinders 4 inches [0.1016 m = 101.6 mm] long formed the water capacitor of the fuel cell in the volume of water. The outside cylinder was 0.75 inch  in outside diameter; the inner cylinder was 0.5 inch [12.7 mm] in outside diameter.

Spacing from the outside of the inner cylinder to the  inner surface of the outside cylinder was 0.0625 inch [0.0015875 m = 1.5875 mm]. Resonance in the circuit was achieved at a 26 volt applied pulse to the primary coil of the toroid at 0 KHz, [ this must be a mistake/omission/alteration !?

Variations of the process and apparatus may be evident to those skilled in the art.

I take it that this is a quote from a SM patent (the watercar SM, not the TPU SM)

Here the "resonance cavity" i.e. gap between the inner and outer tube is given as 1.5875 mm (see quote)
the length of the tubes is given as 101.6 mm (see quote)
Divide the two:
101.6 / 1.5875 = 64
that means that tube length (i.e. height of water column) is seven octaves of the gap and thus auto-resonating to the same basic freq.

And at the same time:
outside diameter of small tube is given as 12.7 mm
the length of the tubes is 101.6 mm
Divide the two:
101.6 / 12.7 = 8
that's 4 octaves and thus auto-resonating to the same basic freq.

[saintpoida]

ok guys its late here in oz i think i have the circuit complete

i tested with voltmeter and while i couldnt see pulsing (using digital multimeter)
the voltage would change when i changed frequencies

and then i didnt have any bulbs on hand so i just put a diode accross terminals
and while it didnt pulse so much i could change the colour of it by changing frequencies

so i assume its working? tomorrow i will get a proper bulb and see how it goes

but my altmeter isnt working? Could i have wired it up incorrectly? i followed the diagram
but im thinking the diagram and my altmeter have different positive / negative, i cant
see the needle move at all so im not sure?

anyone have suggestions on that?

thanks
pete