Stanley Meyer replication with low input power

[mike21245]

Hello all,
I tried to post this in the proper location, so someone please move it to where ever, Thanks.
I would like to share my thoughts on Meyer here. First, though, I would like to say that there are quite a few people who know exactly how this works and have operating examples performing flawlessly at over 10OU particularly at Cal-Tech and MIT. So, there is nothing new or any great secrets here. Also, the following is my line of  thought on this matter and I am not suggesting anyone change their thinking. So ,I will look at the obvious and then work my way out on a limb. I will be brief.
Look at a cross section of one concentric tube combination, dl at the bottom and follow the energy of one pulse from the outer ring to the inner, the energy density increases as it travels inward, this happening upward as the pulse travels up the outer tube reverses 180 and returns to the bottom. As the charge increases in the water the tension across the molecules increases. Consider the tension of a string gradually increasing, at some point , the ability to transfer energy most efficiently is reached. Keep this in mind as efficiency factors.

Farah asks the right question. ?what do you want this to do??
Both Meyl and Bearden describe scalar waves as emanating at right angles from the axis of the energy differential of a dipole or antenna. Meyl?s  3 dimensional vortex model fits in here nicely. 6 vortexes points in, energy traveling across any axis is through the adjoining, each at right angles to one another to the originating axis. The same is true coming back through the unused vortex pair. At equilibrium energy is balanced . Torque and stretch one axis of  the vortex matrix and let it snap back and you will cause the energy of the adjoining rt. Angled vortexes to be given off as a scalar energy burst. Regauge and repeat and essentially a scalar pump is created. Luckily, in the cell all the molecules are aligned on a radius between the tubes. The scalar radiation at right angles to the radius form interference patterns as they intersect. The scalar interference patterns traveling through the outer tube pass through magnetic fields surrounding the iron molecules and here an electrical gain is achieved. Pausing the pulsation is necessary for the breakdown of the water consume the additional energy charge. From my point of view this is brute force electrolysis where the heavy lifting is accomplished by the conversion of radiant energy.

Now, you can?t just pulse this setup and expect a miracle. If you examine some of the ou devices, weather it be Gray, Dollard, Meyl, Bedini, there is one commonality, coils that are wound mirror image with reference to one another. None of the patents will show this. Pancakes are best, but a variation of a pancake is also possible wound in equal layers and direction within, but each opposite. What is created is energy of opposite rotation which when applied torques the water vortex matrix.

At the vic, the pulse from the secondary fires the pancakes wound upon the same core. A problem here is that energy travels faster though copper and is impinged at the stainless copper junction. This problem can be resolved by a resister or lc or just stainless wire if you can find it.

The gain in the outer tube produces a pulse out greater than the pulse in, opposing the field in the vic and input current drops. The diode stops the pulse out from resolving the charge of the inner tube. The coating on the inner tube serves nothing more than insulation preventing the charge from resolving and prolonging the scalar effect as per Bearden.  Meyer thought of using delrin in production because of the time necessary for conditioning.

There is a catch 22 here with the length of the tubes. The second harmonic of the tubes is only known after you cut  them and connect the circuit. Changing the length changes everything, so use a single short tube combination to start, an overtone of A or C or F, as multiple tubes can bring in adverse harmonics unless identically tuned. The length of the larger tubes will be a function of the vic.

I  have tried to address most of the major issues here. Once I can find time to get things up and running, I will post any changes to my scenario here.
This is the jist of the path I am following. Print this post is a keeper.
Regards and best wishes to all.

Mike

[starcruiser]

@Mike,

So you are saying that you have a functioning unit? Or is this your plan/hypothesis on the function and your build plan will use this assumption?

[engineer1]

Come-on Guys a first year electronics student will tell you that resonance means that the hydrogen cell is really a capacitor in series with a inductor and a frequency injected into this circuit will have a resonance if the capacitance and inductance is equal and the proper frequency is found to stimulate it to oscillation making a voltage amplifier( which is the True and ONLY amplifier in the world) You can put 10 volts into a resonant circuit and you will get out 100 volts it all depends on the "Q" of the coil or inductor. The  resonance circuit will only need small amounts of voltage to perform this process and break down the water to hydrogen and oxygen. The secret guys is to find the resonance of your cell and adding the proper amount of inductance. You must first know how much capacitance your cell has and then add inductance to equal it and then find frequency that makes it resonate. Not easy but simple in theory. You need a square wave frequency generator where you can control the time and spacing of pulses and the amount of current will be small.(small current small heat generated Have a nice day!
Study resonant circuits and how to build them. (Stan's clues are all there you just have to  look for  them)

[demartin]

The water cell functions as a low resistor and capacitor in parallel. Without the resistor, the resonant behavior would be easy to calculate and measure. But with tap water's conductivity (four to twenty ohms) the Q is quite low and thus the resonance (in an AC series resonance circuit) is hard to pinpoint. When you run an AC signal through the inductor and water cell, then into a resistor across which you measure the voltage to gauge current, without the resistor you'd get a nice peaking of the voltage at resonance. But like I said, in practice I haven't noticed much peaking at all due to the resonance being so diffuse.

But as others have pointed out, this isn't really an AC series resonant circuit. It's said to be a DC resonant charging circuit. But the equation's still the same. See this link - http://www.richieburnett.co.uk/dcresist.html

I built what's supposed to be a VIC. It has the toroidal transformer, the blocking diode, the bifilar coil, everything. And guess what, it doesn't really do anything. Then I accidentally connected what was supposed to go to the beginning of the second bifilar wire, to the end instead, leaving the beginning free floating. And suddenly I was getting max power delivered to the water cell and clear resonant behavior too. If you want to see, watch my youtube video:

        http://www.youtube.com/watch?v=YSmxliLwhT8

There you have clear resonance happening -- way more than with either the second bifilar inactive or connected in series. What's up with that?

[Arrec]

@demartin:

I think you created a parallel LC circuit with the capacitance between the secondary and primary. You are tuning into the resonance of that circuit, the circuit impedance will be the lowest at that frequency, allowing maximum current to flow through the electrolizer and lamp.

It looks promising, but I do not think it has anything to do with resonance of the 'water capacitor'.

Now here's my idea about the water capacitor (and much of that has been said before here)

There is no way you will get decent resonance with a 'capacitor' that has both plates in a conducting elektrolyte. Period. The resistance of the water is so low (in a typcial Meyer pipe setup (pipe 20 cms) you'll find 10 ohms or so, and if you use demineralized water about 100 ohms if you are lucky, because you will never get your hands on 100% pure water). This so called capacitor cannot ever build up a charge because it will leak away immediately. Don't get confused if you find a small potential across the plates - that must be a simple galvanic cell effect produced by the water impurities and somehow a chemical difference between elektrodes, maybe the deposits. This is how Volta discovered the battery.

Now, if Stan Meyer's invention did really work, there is something we do not know (hey, again I am stating the obvious :-) ).

Let's start with the 'water capacitor'. If you really want to make a capacitor with water as the elektrolyte, you will have to do something about the ion current, bu t still allowing H2 and O2 to form at the elektrodes (or are they not forming at the elektrodes? That we do not know for sure).

So, insulating the plates may do the trick. But then, I do not know how H2 and O2 will form.

Another option is to insulate a large part of the elektrodes, but leaves small part uncovered, to allow H2 and O2 to form there. A small leakage current will then always be present (isn't Stan Meyer in his patent saying that a small leakage current cannot be avoided?)

In his patent he also states that the pulse train causes the potential tp increase up to 1000V. This is not possible with uninsulated plates. If an elektrical field of 1000V is to be applied through the water, I'd say insulation in some way (deposits? paint? partly only?) is necessary.

Or else the notion of a 'water capacitor' is just to put people on the wrong track.

Good luck!