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Overunity Machines Forum



Formular to calculate energy per liter of HHO gas

Started by hartiberlin, August 21, 2007, 02:18:30 PM

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0 Members and 2 Guests are viewing this topic.

oystla

OK, once more;

Anyone collecting H2 and O2 gas together in a chamber and measuring the total volume in liters produced can use the following formula to calculate the efficiency of the electrolysis cell ;

EFFICIENCY = 7744* V1 / (U*I*t)   where

V1= Collected H2/O2 volume measured in liters
U = Electrical input voltage
I = Amperage during electrolysis
t = Time of electrolysis measured in seconds

multiply above by 100 to get % efficiency


regards
?ystein

kinggeorge

I had a post (Do not remember what forum) from someone Running (external powered) Electrolysis to Fuel Cell and its water by product back into Electrolyer cell. He reported that after a while FC woould take longer and longer to convert GAS, lower power from FC and at some point water had to be replaced, He felt that he may have been creating heavy water, but did not have analysis equipment.
George King
georgeking@cosmicsalamander.com


Quote from: xingu on September 01, 2007, 06:13:06 AM
I've been playing around with water electrolysis for quite a while now.
A question: does your formula also apply for distilled water splitted in H2 and O2? Because HHO is a little different from H2O.
If so, then what about the following figures. To produce 10 cm3 of H2 and app. 5 cm3 O2 I need 2 volts and ,31 A during 300 seconds. And these are probably conservative numbers, because my measuring equipment is not the best there is. So the energy input is:
2V x ,31A x 300 secs/3600 secs
I know this is a slow process, but I got these values over and over again, although I ran into problems using the same water over and over again. It seems to me the characteristics of water are changing.
As power source I use a Philips PE 1512 Lab power supply and a common available electrolyzer.
But I have great difficulty in accepting this to be overunity.

Kind regards


ForeverBlissed

So the question I have is how many watts is required to run a typical car?

What about an SUV?

If we uses Miles per Gallon to figure for cars, how many Watts per Gallon is Water?

Let's assume that it takes 12 Volts times .5 Amps to produce 1 liter of Hydrogen within 60 seconds...

Is that enough Hydrogen to run a car?  What about an SUV?

It sure would be great to have a spreadsheet that did all of this calculations for us.

That way we could figure out that once we reach X number of liters of hydrogen per second, we have a usable system that will produce enough energy to run a car.

Anybody want to tackle this?  (it's a little out of reach of my math skills)

FB

Humbugger

Quote from: ForeverBlissed on September 07, 2007, 12:36:35 AM
So the question I have is how many watts is required to run a typical car?

What about an SUV?

If we uses Miles per Gallon to figure for cars, how many Watts per Gallon is Water?

Let's assume that it takes 12 Volts times .5 Amps to produce 1 liter of Hydrogen within 60 seconds...

Is that enough Hydrogen to run a car?  What about an SUV?

It sure would be great to have a spreadsheet that did all of this calculations for us.

That way we could figure out that once we reach X number of liters of hydrogen per second, we have a usable system that will produce enough energy to run a car.

Anybody want to tackle this?  (it's a little out of reach of my math skills)

FB


One horsepower is 745.7 Watts.  I'll contribute that well-known fact. 

Also, it sounds like 6W per liter per minute would be a fantastic achievement, about 21 times better than what Stefan is suggesting represents unity.

dlwammo

For me, the formula is rather simple...

mpg(w/cell) > mpg(wo/cell)

anything else is just gravy...
Don't mess with old farts... age and treachery will always overcome youth and skill!