David Bowling's Continuous Charging Device

[sm0ky2]

Being lead acid batteries have lead electrodes for pos and neg, is one different than the other only by way of charge direction from the start? Like you can get motorcycle batteries without electrolyte, and they have voltage when it is filled, so one of the electrodes must have been pre treated before assy.

Will have to look that up.

Mags

Only directly from the manufacturer, prior to testing


Otherwise, you damn near need gold wire to drain it completely
Or run a low resistance load for long time after it stops running.


But yes, when charge drops to 0, there's no acid in the battery.
This is the same if you had bought the plates yourself to
refurbish an old plastic case.


They run on water


The plates break down (well one of them does)
Which one depends only on the polarity


It's basically electrolysis
That self reverses as we use the electricity
It's an SO4 fuel-cell

[sm0ky2]

Hydrogen would rather be water, but SO4 doesn't like to be lonely.
(in its excited state)
We could do the same with just water, but then we have to store
bulky gasses.
In the acid, O2 just bubbles to the top then reabsorbs
when we drain the charge.

[plengo]

I am kind of ashamed for saying this after so many years have past from the beginning of this thread: I did a few nights ago this exact same setup and tested, and it worked!!!


Re-reading Turin's comments after my first post (with a picture of the setup - an schematic of sorts ) I realize how true are his statements. I am impressed. All theses years and the phenomena is right in front of my eyes. The dead battery.


That "bad battery" is working as a resistor, as a capacitor, as an inductor and all at once. The words "balancing", that I found on pages before is indeed relevant (i am reading everything again from the beginning, so it will take a long time for me to be posting here again).


Allow me to express my thoughts, and if I am far from your understanding about this 3 battery system, let me know, I want to learn.




A Dead battery will have an almost infinite resistance therefore the initial current going through the circuit will be small and the motor not running shows that. As time passes, some of the current coming from the 24v two batteries will eventually get inside the Bad Battery and start to charge. Now BB (bad battery) is becoming a capacitor, and it's internal resistance starts to drop.


Mean while we have a pulsating motor that will literally pump current back and forth, converting a direct current into a sort of AC. Spikes are visible on wave forms from pictures and videos from others and also from mine own measurements on my setup.


Those spikes causes Energy to be stored on the BB, "desulfating" it (as some say) and therefore new energy comes in. New energy comes in from that phenomena of Radiant Energy inside the battery creating energy. Bedini said that exactly in one of his first videos series. He said the "SSG" electronic circuit has nothing special about it, the free energy comes from the Radiant Energy inside the battery.


As the BB starts to develop voltage, current will decrease and the motor will spin less and therefore less radiant spikes or AC-DC pumping, therefore, BB will start to become a battery and an Resistor for the other two batteries, follow this and all 3 batteries will be dead, except?


Except we let them rest, balance the load on the motor that controls current flow dynamically, don't let BB become a good battery by keeping it under constant load, preventing it from becoming a battery and a load.


Those radiant spikes i saw on my oscilloscope were there and they are going towards what? towards the BB, and this will cause that BB to become rejuvenated again but we don't want really only that, we want it to be rejuvenated only enough to allow the "free energy" to be quickly used up instead of depleting batteries one and two. That will keep the voltage differential high enough for running an LED or motor.


The motor is essential, the BB is essential. I would imagine then that a better pulsating motor, or even an SSG would improve things.
This BB cannot perform just like a capacitor only neither as a resistor only. It must be that line where it becomes extremely efficient converter of Radiant Energy spikes into current that counter-balance the motor AC pumping which causes for less energy to be taken from Batteries 1 and 2.
Literally BB becomes an elastic capacitor with Batteries 1 and 2 dancing to the rhythm of the AC pulsating motor, bring now the scooter motor modifications that make it pulse in both positive split poles (Battery 1 positive and Battery Bad positive poles) symmetrically.


Uff, i think i just burned a few cells trying to old fart around here.


Fausto.

plengo,
That's the setup. You got it right the first time. I'm glad you are seeing some success. Just don't make your runs too long, and batteries one and two will always recover. I don't know how many runs you can make on the system before you have problems with batteries one and two recovering, but I know I have pulled out way more energy from my setup than batteries one and two could possibly hold. My kilowatt meter tells me that, so it's a FACT, not a "belief." And they are still holding their voltage. And it is NOT a surface charge on batteries one and two. I have tested that also..voltage under load. AND I have had the energy produced by my motor hooked up to my energizer for free.  So am I producing more energy than the system takes to run? Absolutely, positively, unquestionably, Yes. I need a kilowatt meter that doesn't reset, so I don't have to watch everything so closely, because the minute I shut down, you lose the present run reading. So I always have to write down the reading before I shut it off, and then add it to my total output. But at least it works.


The issue is not what I can do with this system, but what YOU can do. Can you repeat these results? Can YOU find a really good "bad battery" (an oxymoron if I've ever heard one) and make short runs until your kilowatt meter tells you that you have far exceeded the power that two batteries could possibly produce. Then can you make longer and longer runs until you learn to watch the good batteries and kill the power when you see them begin to go down, so you can let them recover. And then how do we make it better.


plengo,


Possibly your solution is the simplest...keep a huge load on battery three, so there is no chance it will charge. I have wanted to try different diodes and resisters, but am trying to get things welded up for my energizer and it's taking all my time away from more experimenting on my setup. Tell your friends and neighbors and let's get more and more people involved in making a working system out of this. The solution is here somewhere. We just have to find it.
Dave

[plengo]

btw,


it is good to be back here. I see Magluvin still here, Luc and many others that I truly respect. Great guys.


Fausto.

[Vinyasi]

@Dbowling,

After I have replicated your setup then I can take a look at your new idea. Small steps.....

@Pese,

Please read the text again. I said "dead". This means that something is not exactly, but
pretty close to reality. Then I said >a very high internal resistance< this is on the opposite
scale of zero Ohm. High Ohm equals low current. Low Ohm equals high current.

Now let us talk about a "dead" battery. It is not just a battery. It is a device that has a high
internal resistance at very low voltage. It will climb to a relative high voltage very fast when
you try to charge it. It will drop to a relative low voltage very fast when you try to discharge it.
It is behaving more like a big electrolytic capacitor than a battery, but the internal resistance
is opposite of a electrolytic capacitor regarding charge and voltage. A capacitor has a low internal
resistance when empty, a "dead" battery has a high internal resistance when empty. OK?

Groundloop.

Thanks for this analogy. It helps make it more clear that Dave's setup is more like an electrolytic capacitor, then like a plain capacitor.

I would like to make a suggested improvement.

Alter your analogy such that a normal capacitor replaces the electrolytic.

And negate the resistance, but keep it low lest the circuit's output rise too fast!

Do these two things by replacing the dead battery at position #3 with a good battery and place two items behind it (between its negative terminal and the negative terminal of battery #2), namely: a negative resistor and a normal capacitor.

The capacitor will turn this circuit into an A/C circuit and thus will not significantly drain the three good batteries and will require that the motor load be able to handle an A/C input. So, the third alteration is to replace the D/C motor with an A/C motor capable of a frequency far less than 60 cps. More like...milli or micro Hz range.

The capacitor will boost the gain at a rate proportional to its capacitance.

The negative resistor will drive this circuit in as much as the output will escalate, or else it will diminish, depending upon the absolute value of this negative resistance, high or low respectively.

The negative resistor may be replicatable by the use of Aaron Murakami's plasma arc.

http://is.gd/plasmaarc

Since the plasma arc was designed and intended for a D/C system, then two of these plasma arcs are placed in parallel with each other and each protected by their own diode (one diode facing one way and the other facing the opposite direction to accommodate the A/C circuit surrounding them).

References...

http://is.gd/acplusdc

http://is.gd/plasmabattery