Is this circuit good?

[NerzhDishual]

@Guruji

This schematic is the very one of the J. BEDINI SSG 'energiser'.
It is just redrawn from J BEDINI (with and added potentiometer).
It is not from me. I guess I found it in this forum.
I do not remember where...

The neon bulb has no effect on the charging process.
It is only here for protecting the transistor when/if the charging bat
is disconnected. It only glows when this bat is disconnected and could
be an usefull indicator of the functioning of the 'energisers'.

Best

[guruji]

So if I disconnect the charging battery with that schematic of mine the transistor would blow up?
Thanks Nerzhdishual

[nul-points]

So if I disconnect the charging battery with that schematic of mine the transistor would blow up?

not necessarily - the neon is there as protection just in case - it would depend on how large the spikes are, how long you operated the circuit without the battery to be charged, the voltage rating of the actual transistor used, etc

but since there is a good chance of damaging the transistor without a charging battery connected it is best to have the neon connected

PS if you do the LED tests above, it's a good idea to check the LED first - i'm sure you would do this anyway!

all the best
sandy
Doc Ringwood's Free Energy site  http://ringcomps.co.uk/doc

[guruji]

Hi Sandy I did those tests and yes the led lit up on both sides even when turned the other way.
Is there a way to measure the Bemf now?I will do the neon now.
Nerzhdishual it's better to use 10ohm resistor than 680ohm with the variable resistor?
Thanks guys.
Andrew

[nul-points]

hi Andrew

if you are getting Bemf with the circuit as you showed above, then it will be difficult to see as voltage on a scope and difficult to measure as current with a meter:

the Bemf collecting diode (1N4007?) will limit the voltage across itself to around 0.6V - so if you do have a scope & can turn the Y gain up to say 0.1V/div you may see a short pulse, around this voltage, measured across the diode every time a magnet on the wheel passes the coils

although the Bemf pulse voltage has been limited to around 0.6V, the current is not limited by the diode so the Bemf current will flow into the battery - and the impedance of the battery to the pulse will limit the current

it will be difficult to measure the Bemf current with a meter because it is unlikely that a regular meter will give a true reading of such a pulsed waveform

if you have a scope you could try adding a small-valued resistor (measured) in series with the Bemf diode & 'battery to charge' - with a 'data-logging' type scope it is possible to get the average of the pulsed voltage across the series resistor and then work out the average current thro' the resistor - hence find the Bemf current

another way would be to replace the 'battery to charge' with a large value capacitor (the largest you can get at a rated voltage greater than say 40V - connect a variable resistor in parallel with the capacitor

what value of the resistor just keeps the voltage across the capacitor at around 12V?

this will give you an indication of the amount of load that the Bemf circuit can drive - 12V / (resistor value) will give you the average Bemf current into the resistor load and then you can work out the power (& energy for a length of time)

remember that if you use a polarised (eg electrolytic) capacitor then the +ve terminal must go to the Bemf diode shown in your schematic/circuit  and the -ve terminal to +ve voltage rail (just like the battery connection)

hope this helps!
sandy
Doc Ringwood's Free Energy site  http://ringcomps.co.uk/doc