Gravity Mill - any comments to this idea?

[ooandioo]

tbird,

I agree, if you reduce the diameter of the exit pipe, you are able to lift the water higher. What I mean is, if you cylindrical scale down the pipe exit (see turbine) you would create a water jet, but therefore need more power for the shuttle and would gain nothing? Agree?
This is what I red out of your post.

Andi

[tbird]

andi,

NO!  i don't know about a turbine how you are comparing it here, but here we have moved half of the area (= i/2 weight of water above) to another place in column with the half lift behind.  now the pressure focused before on the total area is focused on half the area.  to stop the piston, you have to have as much weight opposing the piston as it displaces.  since it won't fit in the already occupied half, you can only go up.  this doesn't change the weight, just its location.  if the pressure of the shuttle doesn't change, and it won't because we didn't change the volume of the shuttle, then if we only had half the area to exit the water in, the load on the piston would be halved.  this would allow it to push the 1/2 remaining water harder, thus higher.

"sometimes a potatoe is just a potatoe".  let's not make this harder than it is.

tbird

[tbird]

andi,

i understand what you mean now.  you don't have to add more power because you still have the power available that was pushing on the half that is restricted.  it won't just go away. it goes to the load presented, 1/2 volume exit pipe.

tbird

[hartiberlin]

All. I am again awake and TBird is right. With a constant pressure from the shuttle going up, you can get the water higher, if you squeeze the tube exit. Your garden hose example is perfect, as the pressure from the watercompany delivered to your hose input  is constant !

[tbird]

hi stefan,

THANKS FOR COMING TO MY RESCUE!!

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