A machine to convert gravity to mechanical energy # 2

[brian334]

Hans,
u r embarrassing yourself.

[mondrasek]

Brian,

As my examples have tried to show:  Take a cylinder of any diameter and length combination that has an internal volume of 1 cubic foot (displaces 64 lbs of water).  Volume of a cylinder Vc=L x pi x r^2 where L is the length and r is the radius (half the diameter) of the cylinder.

Once you have selected a diameter or length and calculated the other so that you have a cylinder with a displacement volume of one cubic foot, consider it placed in water so that the top surface of the cylinder is at exactly the top surface of the water.  If you then calculate the force of the water pressure on the bottom surface of the cylinder, you will find that it is also exactly 64 lbs.  Since your weight inside is also 64 lbs, it will not expand. 

To gain momentum as you wish you must let the cylinder fall deeper.  But the deeper you go, the higher the force on the bottom surface becomes.  It starts at 64 lbs and increases very fast.  This has also been calculated for you several times.

There is absolutely no way you will gain momentum that will overcome the force of the water that is opposing the cylinder expansion.

It is a wonderful idea and looks great on paper to anyone who does not completely understand that gravity is a conservative field (I have been guilty of that myself quite recently).  It was so well thought out that it took me awhile to actually find the physical flaw, even though I knew it could never work from the start.

Please consider all of the posts explaining why this will not work again with an open mind.  They are all correct in there own way.

M.

[hansvonlieven]

no Brian, you are.

You say: Water weights about 62 lbs/cu. ft.

OK. That means you have a pressure at the bottom of 62 lbs per square foot.

At a depth of two feet you have twice that because you need to take into consideration the foot of water above it. At a depth of three feet you have three times that and so forth. You forget in your calculations the weight of the water column above the tank.

As I said before you need to study hydraulics since you obviously don't understand it. My calculations are correct.

Hans von Lieven

[hansvonlieven]

@ mondrasek,

You are also forgetting the mass above the tank which exerts a pressure which has to be overcome.

Hans von Lieven

EDIT: the pressure at the bottom of a 10" tank is about 620 lbs per square foot this being the weight of a 10' column of water with a footprint of 1 square foot

[brian334]

Hans,
Water in water does not weight anything.
Mondrasek,
It is not the cylinder that builds momemtum, it is the internal weight that builds momentum.
I don’t think either one of you understands the invention.