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Overunity Machines Forum



Joule Thief

Started by Pirate88179, November 20, 2008, 03:07:58 AM

Previous topic - Next topic

0 Members and 97 Guests are viewing this topic.

jadaro2600

Quote from: xee2 on March 16, 2009, 02:26:20 AM
@ jadaro2600

Your circuit is functionally equivalent to a JT with the wires forming the transformer. The capacitor in series with the LED blocks DC but will pass AC and the LED can be lit with an AC voltage. AC meaning any voltage which is not at a constant DC voltage level thus pulsed DC would be considered AC in this case.

As the current starts to flow in one wire it creates an increasing magnetic field around the wire. This increasing magnetic field then creates a current in the second wire. Two wires twisted together make a very simple transformer. Making the wires longer will increase the current produced in the second wire. Adding iron or ferrite near the wires will effectively increase the electrical length of the wires and thus also increase the current produced in the second wire.

You seem to be the only one actually doing JT research. BTW, PNP and NPN transistors are functionally identical except they use opposite polarity voltages and adding two capacitors in series creates a combination with half the capacitance and twice the voltage capability.


@xee2,

This is good news - to have some questions answered! thank you xee2 :)  This might solve my high voltage problems, I'm lacking any capacitors that could hold better than 500 volts, and I'm wondering if there some way to connect them so that I can mathematically dumb down the results.  SO, connecting them in series will cut the voltage ( divided by the number of capacitors - given they're identical )?

I've been calling my twisted pairs a linear transformer - they're also called gimmicks if they're used as a capacitor.  I'm hoping that these simplify things for any numbers that my evolve out of it - they would be independent of any ferrite or iron after all.

@Pirate88179,  These are from the shack - sorry to disappoint you, :( ..they're the standard semicircular plastic ones.  I too recently ordered a bunch of stuff from electronics goldmine, but I have yet to receive any tracking information.  If you ordered the ones made of metal, I commend you, they do seem more  physically sound than these plastics.  It's really hard to monitor temperature on the plastics, either they're smoking or they're fine. ...and if they're operation is in question, testing with a finger usually winds up in a scald. :P.

I obtained a pint of magnetic pain for $13 - but I haven't wanted to do anything today ( it's Sunday ).  The container is made of plastic with a metal lid.  Out of curiosity, I brought a magnet near the side and it sticks - which is good news - sticks on the bottom too.  Moving the magnet around on the surface produces odd shifty sensations.

@all,

I'm having a hard time figuring out how to measure output voltage in my circuit.  I can drop the capacitor on the right side of this and add it somewhere else - I have plenty of switching diodes for rectifying - but there is no 'pickup coil' in this design - otherwise things would be easier = just bridge rectify the pickup coil and bridge the output terminals with a high voltage capacitor and take a measurement.

Looking at my previous diagram, has anyone got any suggestions?  I'll post another one with more working are - feel free to take it to paint :P

jadaro2600

I got bored and made a PNP type Joule Thief circuit diagram - tested it; it seems to work fine also.  Blue indicates the negative side of the circuit - notice I flipped the battery.

gadgetmall

Quote from: innovation_station on March 16, 2009, 12:03:24 AM
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xee2

@ jadaro2600

Quote from: jadaro2600 on March 16, 2009, 03:03:10 AM
( divided by the number of capacitors - given they're identical )?

Yes.

Does your circuit work without the 1 uF capacitor? 


NOTE: The following circuits are for AC inputs. The input voltage must be greater than 0.7 volts for peak meters and 1.4 volts for full wave rectifier in order to bias diodes on.



jadaro2600

Quote from: xee2 on March 16, 2009, 11:19:25 AM
Does your circuit work without the 1 uF capacitor? 

No, but with reduced capacitance.

*edit "It will work with a smaller capacitor"