Connecting to the Wheelwork of Nature

[sm0ky2]

how difficult would it be to design a system to oscillate as low as 33.332Hz ?

[IceStorm]

Hello IceStorm,

I have a Gauss meter which can transfer its readings into a computer, but I believe it would only measure the magnetic field and not the dielectric field.  I suspect (but do not know) that any anomalies will occur in the the dielectric field.  My thinking is that the transients which occur at the edges of a square wave are caused by the following:

As a dielectric field expands, the charge itself expands at superluminal speeds, while the ions created from the initial charge expand at near-light speeds.  Once the voltage stops increasing, the dielectric field (being massless) stops its expansion immediately, while the ions continue expanding out for a short period of time as a result of their kinetic energy.  This short continuation of the ions' flight results in the increased voltage readings of the transient.  When the field collapses the process is reversed, and a short 'undershoot' transient occurs.  If this is the case, then the 'height' of the transients would seem to be an indicator of the strength of the field that was formed, at least relative to the same readings of other frequencies.  Also assuming that field strength is directly proportional to the potential used to form the field, this would result in a comparative field strength for different frequencies, where all frequencies are generated with the same voltage levels.

Concerning potential vs field strength, do you think the test would be more accurate if I measure the transient voltage as well as the current?  I have a Tektronix current probe ordered which is good for up to 50 Mhz, but it seems to be lost in shipping somewhere at the moment.  Do you have any other ideas/suggestions for measuring the dielectric field strength of the transients?  Do you think I'm on completely the wrong track? lol

Thank you for your consideration of this matter,

Neo

Hi Neolystic,

             The dielectric field as you refere is more a mathematical description of what happen when a electric charge is created and interact with the surrounding space for a specific vector.Its not measurable but a tensor product for a specific electric charge who can be different at each vector if something interact with it in the specific surrounding space like air,water,metal etc.

To your question about if you should monitor the Current as well as the Voltage, i think you should, take for example a step up transformer, you feed it with 10v 1 amp and for example 400 go out at the output, that dont mean you have more energy out ,in a perfect world you will have 400v and 0.025mAmp at the output for a coil ratio of 1 in, 40 out so no gain , just different potential with the same power output.

The collapsing field act as a step up transformer so with only the voltage reading to read any gain/loss is not really accurate.

And no i dont think your on the wrong track, if you ask me if at the end of your will find something i can answer yes or no but who i am to answer that. Like everybody in this forum who experiment and put idea to a concrete realisation there 2 end , validation or refutation, and in both case you will learn more and more so you cant be in the wrong track.

Best Regards,
IceStorm

[IceStorm]

hi , forget to add, if you don't have a current probe, just put a 1 ohm 25W resistor and clip the Ground of the probe at one leg and the probe at the second leg , and with the Ohm law V =I*R its easy to have a reading with 1v per division, each volt equal 1 amp.

Best Regards

[Neolystic]

I'm a bit confused.  Here is the meter I have to read the E and M fields. http://www.detectortechnologies.com/store/detail.aspx?ID=28   My meter has the 'flat frequency response' and 'output jack' options.  I talked to the manufacturer of this meter, and was told that the 'Electric' setting for the meter measures the dielectric component of the field.  If this dielectric component is just a mathematical construct, and is not measurable, what would this meter be reading?

Thanks,
Neo

PS they found my lost current probe ... it will be here next week!

[IceStorm]

I'm a bit confused.  Here is the meter I have to read the E and M fields. http://www.detectortechnologies.com/store/detail.aspx?ID=28   My meter has the 'flat frequency response' and 'output jack' options.  I talked to the manufacturer of this meter, and was told that the 'Electric' setting for the meter measures the dielectric component of the field.  If this dielectric component is just a mathematical construct, and is not measurable, what would this meter be reading?

Thanks,
Neo

PS they found my lost current probe ... it will be here next week!

There nothing wrong with your meter , it read:
Electric Field
Magnetic Field
Radio / Microwave

A good explaination for the E field can be found here : http://en.wikipedia.org/wiki/Electric_field

Best Regards,
IceStorm