Air Buoyancy Machine

[TinselKoala]

When you put the ball into the tank, it displaces an equal volume of water. Where does that water go? Ignoring the leakage into the trap, the water that the ball displaces makes the top level of the water rise. You have raised a volume of water from the bottom of the tank all the way to the top, just by pushing that ball in at the bottom. That takes work--an amount equal to the work obtained by letting the ball float to the top.
Now figure in the leakage into the trap. This must be pumped out, by the pump--all the way to the top of the tank. That takes work, and there isn't any balancing work coming in, so it is a total loss.

Maybe you should look closer.

[brian334]

There is no doubt in my mind that there are a lot of junk inventions out  there. Just because there are junk inventions out there that does not mean my invention is juke.

[TinselKoala]

Brain, you are clearly a creative guy. Your hurricane eyewall surfer is really cool. But your buoyancy engine has a very simple and clear flaw, as I have tried to show you in the video. If you read and try to understand the various analyses of buoyancy drives on the Simanek site I linked, you will probably be able to see that your idea isn't new, and it is functionally identical to those other drawings that you call "Junk inventions."

But even if you don't care to go over Simanek's analyses, you should really think about, and try to address, the point I make in the video above. How do you lift that water back up, without using up all the work you get from the floats?

[brian334]

Post your trash inventions somewhere else.
Post your trash inventions somewhere else.
Post your trash inventions somewhere else.

[Alien509]

When you put the ball into the tank, it displaces an equal volume of water. Where does that water go? Ignoring the leakage into the trap, the water that the ball displaces makes the top level of the water rise. You have raised a volume of water from the bottom of the tank all the way to the top, just by pushing that ball in at the bottom. That takes work--an amount equal to the work obtained by letting the ball float to the top.
Now figure in the leakage into the trap. This must be pumped out, by the pump--all the way to the top of the tank. That takes work, and there isn't any balancing work coming in, so it is a total loss.

Maybe you should look closer.

If I dropped someone down a sealed 1000 foot shaft into the ocean then locked down the bottom ten foot of that shaft and opened the bottom of it, would that person not feel a force greater than what it took for me to drop them in? Think about it... and no there is no overflow into the sealed section of my device.

I commend your efforts Brian, and I wish you the best of luck in further theory.