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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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0 Members and 13 Guests are viewing this topic.

void109

Nice circuit you've posted, very trimmed down.  I was playing with it, and as you increase the load resistance you have to increase the induction proportionally.  Its kind of creepy how if the induction is sufficiently larger than the load resistance, the output versus input goes up dramatically.

Its too late or something, I honestly dont understand the outputs - I dont understand how the output can sustain so much longer than the input.

Here's a variation (see attachment)

Magluvin

Very good Void.
It is doing the job well. I changed the coil to 2mh and works well also.
I think the sim needs simple.   But what you have here and my lil circuit, I think its time to put it on the bench and see what we can do.  I have all weekend to play in the electron sandbox.

Mags


void109

I wish I did, the girlfriend's thirtieth is tonight, there's most of my weekend surely, and I have some work to catch up on as well.  This coming week I am going to hammer together a device for sure, probably of the higher voltage variety - as mentioned before, just because I have plenty of components, oh and high voltage experiments are like a geeks' version of extreme sports haha

This is a fun circuit/idea/theory to play with, I'm having a blast, thanks for sharing it! :)


void109

I have been making measurement errors - I think.  Placing a resistor at the beginning or end of the circuit and measuring power dissipated for that resistor I dont believe describes the power consumed by the circuit.  We can use that resistor to calculate the amps drawn from the power source, but we then need to multiply that by the power supply voltage instead.

If we use the circuit I posted the other day as an example, attaching it below, it shows the output load (100 ohm resistor) having a power dissipation of 1.58 KW and the 300mOhm input resistor shows 4.74 watts dissipated.  OU!  Or not.  Instead if I look at the amps flowing over the 300m resistor, I see its 3.98 amps.  3.98A x 400V = P = 1.592KW.

Is this correct?  If so couldnt one of you lurkers skulking in the shadows have pointed that out earlier hehe? :)

void109

Unfortunately I think this accounts for the circuit you posted showing inductor inertia, it's not so straightforward of a case, but if you just watch the amps over the 10m resistor and multiply that by the 50V supply voltage, those 'starting' pulses are huge amounts of power.