Knitel's InfinityPump

[PhiScience]

Hi friends,

I will do some physical experimenting on this to fill in the missing lines below and find the true answer.

Problem:
Can a buoyant weight pull enough water to the top of a cylinder to re-displace it self?

Hypotheses:
Based on the principles of hydraulic and hydrostatic pressure this cannot be achieved.
Or can it?

Materials:
The materials needed to conduct this experiment are still to be determined.

Procedure:
The procedures of conducting this experiment are still to be determined.

Results:
No data has been collected yet.

Conclusion:
?
   
Wayne

[tbird]

hi stefan,

just for kicks, i did some calcs with your numbers.  since your weight in the tube was off by 10 x, i used 200kg instead of 2000kg.  let's see where this takes us.  since metric is foregin to me, i won't be surprised if i make a mistake.  let me know.

5 meters intake tube with 1 cm diameter.
    area of diameter = 1 squared times 3.14 (pie) =3.14 cm2
    weight of water per cm2 = .5kg

swimmer weights 200kg with radius of 11 cm.
   area of swimmer = 3.14 times 11 squared = 379.94 cm2
   weight per cm2 = .52639    since this is more than is in the tube, we can raise the water.

volume needed to float 200kg swimmer; since 1 cm3 of water weights 1 gram, for 200kg of water,
   we need a volume of 200,000 cm3
   200,000 divided by 379.94 cm2 = height (or depth) in cm
   height = 526 cm  or 5.26 meters

not pretty.

we can try other numbers, but i'm sure the results will be the same.

tom

[wizkycho]

Hi all !

1cm2 is surface of water quadratic pipe
100cm2 is surface of quadratic destination container

total weight of water in pipe is 1cm3=1g   times 500cm = 500g
height of pipe is 5m

tbirds claim, if I got it right, that pressure in quadratic pipe is 500g per 1cm2 and that negative preassure is multiplied 100 times cause quadratic surface is 100 times bigger.
so it would be 50000g or 50Kg per 100cm2

I'm going to "attack it" from above
Ep=W*h (W is weight in Kg)

floater-swimmer will have to move 5cm i order to pump up 500cm3
so it did 50Kg*0.05m = 2.5W of work
with this we actually lifted 500g to 5m
and this is 0.5kg * 5m =2.5W

now this says you are right

10cm height in container makes 1000cm3 and is 1kg of displaced water or
88.5cm3 of lead for 1kg (density of lead is 11.3) or
0.885cm of height in container for 1kg of lead so
0.885cm * 60 to have 60Kg for certain start of suction

that makes 53.1cm of height
then I add another 53.1cm of air

container is now 106.2 cm in height and displaces only 10.6Kg

and height of floater is allready over 1m

it dosn't float *************

buhuuuuuuuu my star exploded (but only if you are right)

let's make another one

Wiz

[xnonix]

Clear enough tbird

[wizkycho]

All!

still must admitt I'm still puting in perspective
that even 40Kg is not enough to lift that 0.5kg of water.
that still seems impossible to me.

must make experiment

this is 3D Force times lever width. What a magicall fluid we drink

Wiz !