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Overunity Machines Forum



Stanley Meyer Explained

Started by h20power, March 15, 2009, 06:34:59 PM

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h20power

A while ago I got this effect with Meyer's technology:
https://www.youtube.com/watch?v=hW78gKn1ZZ0


You will notice that there are very few small bubbles and the only way for this to be possible that I can think of is for the gases to be coming of in their monatomic gas state. I am not the only one that has gotten this effect. One thing we all notice is that the gases seems to generate right in the middle of the electrodes and not on the electrodes themselves. So, to honest it's a guess that it is coming off this way but it seems to be a good guess.


I have a question for you, if you don't mind? Who have you seen getting voltages like these with this technology? The only reason I ask is thus far I am the only one that I know of that is doing so. In 2013 at the Global BEM I reached 4.2kv. Latter on that year I reached 5.2kv and as time past I made it to 6.3kv, 7.5kv, 8,8kv, and finally to 9.2kv. With the next setup I should be able to reach 14kv or more if the math checks out experimentally.

pomodoro

 I've been focusing on nanosecond electrolysis at low voltages, so I can't make any comments about HV  as yet. I guess the only comment is that in the video that came up after your link there are 450mA passing at 150V.  That's about 70W if its DC . How much of that do you think  is going into producing the hydrogen?  i guess I'm asking how does that compare with a system that uses 3.5V with 20A?  I'm very impressed with amount of gas coming from DI water regardless of efficiency, as the amount of current causing such quantities of gas on your video should not flow unless there are traces of ions or lots of atmospheric CO2.  In conventional electrolysis, having not much electrolyte is a recipe for huge  IxR losses, so the setup should  heat up after an hour or so of work at 70W, unless something revolutionary is happening, which could well be.  I really have to have a good read of your setup before I ask too many more  stupid questions. What is the best link to your work?

Cheers.

Dog-One

@Ed,

Like your video, but I will tell you this:

If you ever get a true impedance match within your VIC, you better have that cell located in an explosion-proof container.  With those voltages, it will almost for sure arc over and the gas in there will be like Nitro-Glycerin.  Basically, a MAJOR setback.

Right now the only thing that is saving your hind end is that your balance is still a little bit off, i.e. you have your voltage zone near one plate or the other instead of centered.  My recommendation is that you cut back on the power and make adjustments by either adjusting your negative choke or add an external plate capacitor.

You've done a lot of work and I'd hate to see you blow yourself up.  With just a few tweaks you'll discover you do not need nearly so much power going into the cell.  Let voltage do the work, but only after you are properly tuned.


h20power

That was from Meyer's 8xa circuit and yes it pushed amps but had a lot of high voltage spikes to go along with it. The MMW was only 3.0 but that is pure distilled water with nothing added to it. The plate spacing is only around 0.032 inches which a lot of us believe forces the hydrogen to come off in it's monatomic state. When I started getting high voltage there would be almost no small bubbles at all and now that I have been able to keep the B- and B+ voltages to within 20 volts of each other even at 9.2kv there is absolutely no gas production like normal as the current was measured to be only 0.6 mA flowing through the cell. It took me awhile to figure out just what was actually going on with this technology but like I said thus far the math and science seems to follow right along with experimental results. From what I can tell for a cell the size of mines it's going to take around 10.5-11.5kv to get it to just reach the threshold for ionization. For the most part it's works just like an ozone generator breaking the bonds of oxygen molecules with the only difference being the medium is now an semi conductive liquid, water. [/size]


From my research I found several things in nature that separate the water molecules in the same manor by getting at the electrons. One of them does so in the exact same way, it's all written on the page showing the supporting evidence for the theory I came up with. This is how I know it's going to work for it already happens in nature it just took awhile to learn how to get the voltage potential up to Meyer's stated working voltages for this technology. Lots of trial and error let me tell you lots.


Water is just about the same as any molecular gas in that the atoms will ionize at almost the same energy level for it takes 1312 kJ/mole for hydrogen and 1313.9 kJ/mol for oxygen. Something about this makes it possible to break it apart just the same as any molecular gas in a high voltage situation. What is needed is another full study on ionization by the scientific community as I feel they missed something. As for a link to my work I stop sharing awhile ago but I do have some of it on this Face Book page: https://www.facebook.com/True-Green-Solutions-189789027762878/?fref=nf
I just ran into far too many people that only wanted to fight with me and would ignore any science I'd bring forth. So, I left them to their thoughts and from the looks of it they simply ran out of steam now.


And to Dog-one don't worry as at amperages this low it just doesn't have enough energy to make an arc of this distance. The amps never get over 0.6 mA as long as I keep it in resonance no matter the voltage. It seems all that matters is I keep the B- and B+ as close to the same voltage, but opposite polarity, as possible. Plus remember Meyer did this and ran his car down the highway.  Remember that 9.2kv gets divided by ten so it's only 920 volts per resonant cavity. Meyer states that to get this working correctly I have to get between 1000 and 2000 volts per resonant cavity.

Dog-One

Then lower the capacitance of each cell and reduce the number of cells and you should be in the ballpark.