Bob Boyce 101 efficiency details

[TheNOP]

so what is the details of the cell eff.

- 96 cells, wet stack
- 3 independant power supply fully isolated from each other.
a steady current one(0 - 300 volts, 0 - 30 amps) and 2 pulsed DC circuit(fully controlable, can also be mixed)  on their own supply

i did stumble on cells that seem to produce more gas. more then once.
i can't say they were over 100% efficient as i have no way to make shure without isolating those cells.
and when i try to isolate the cells, it kill the "over" production.
together the cells are not over 68% efficiency, compaired to Faraday.
give or take a ~10% error margin, mainly from the gases output that i can't analyse, the method use to collect the gases and the timing method.
while i could probably fix the timing method issue fairly easily, the other 2 need tools that i can't make nor buy.

what else do you want to know ?
but maybe you are not interested in my cells stack since i am not claiming OU.

[TheNOP]

TheNOP,  It's pointless to argue with this guy... everything he says is pretty much irrelevant to what he's responding.

i agree, but i have put it on "language barrier" fault.
english is not my primary language, not even my second one.

Here's the  problem with  measuring Faraday efficiency in series cells.

In a series cell:                    + N N N N  N -            for example.. Running at 12V, at 4A.

If you use  4A to calculate Faraday efficiency,  I think that would give you an inaccurate Faraday efficiency number because, there are more than 4 Amps doing work in the cell...

Here's why....     Each cell is running at about 2 V, and has a current of 4 A running through it... So if you add up all the AMPS performing work in the whole cell, you have 6 * 4 A .. Which is 24 Amps doing work at 2V at any time.   Using  4A might give you 300 percent Faraday, etc.

i find this very on topic and is the true way to calculate series cells.

for those who might be confuse by the 24 amps value while only 4 are said to pass through all the cells, here an other way to see it.
12 volts * 4 amps = 48 watts
2 volts * 4 amps = 8 watts * 6 cells = 48 watts
2 volts * 24 amps = 48 watts

soliloquy
1 : the act of talking to oneself
2 : a dramatic monologue that represents a series of unspoken reflections

  regardless of what WilbyInebriated might think, you are not alone to be interested in that kind of informations.
   

[d3adp00l]

so whats the alleged power consumption on all three power supplies, and what is its output, and in addition what is your proof of this output.

[TheNOP]

so whats the alleged power consumption on all three power supplies, and what is its output, and in addition what is your proof of this output.

i assume you want to see for yourself if i did'nt made errors while calculating.
for a not ou cells stack... ?

you will have no proof from me as i have nothing to prove to anyone, except to myself.
do your own experiments.
and, if you think you have something, and want your peers to review it, post your own data.
as for me, i have nothing interesting to post about my stack else then what i already posted.

68% was the highest result i ever had, with so few gases output that it is not usefull for most applications.

[CrazyEwok]

i love it how everyone quotes faradays numbers as flawed but still is used as a referal to how to measure overunity. Faradays number refers to ampere you all know this right. You want to build a device to kill faradays law? you need to use the same voltage he did. its not watts nor does he state watt or joule or anything like that, its AMPERE. Also faraday's law only applies to those using his voltage. Otherwise it can only be used as a guide. And production of only 1 or 2 % overunity is of no use to us. As we cannot use this sustainably right now. You need to look at approx 400% overunity for use in a ICE, YES 400% (ICE are about 30% efficient and then the alternator at about 80%) so argue all you want over the clause of a few mild percentage points.