Linear piston ratchet engine, 99% efficiency. Proto type in action!

[AlanA]

Terry Miller could do this. He was able to reuse air in to, three and more cylinders. He could run several cylinders with the same air!!!

Alana

[AlanA]

@ Tommey

Just to ensure that I understand you post right (Sorry Englih it not my first language).
I you use 300 psi at 1cu/in and inject it to to the engine, the air that come out of the cylinder is at 23 psi. I am right?

Thanks
Alana

[Tommey Reed]

Just to ensure that I understand you post right (Sorry Englih it not my first language).
I you use 300 psi at 1cu/in and inject it to to the engine, the air that come out of the cylinder is at 23 psi. I am right?

Thanks
Alana

This all depends on many factors, If 300 psi  at 1 cu/in is in jected in to say 1cu/in piston each movment of the piston rod will travel at a psi rate of:
1" movement = 300 psi
2" movement = 150 psi
4" movement = 75 psi
8" movement = 37.5 psi
16" movement =18.75 psi
That is also if the air is turn off after 1cu/in of volume is used at 300psi injector...
I hope this helps...
Tom

[Tommey Reed]

The 300psi injected in a 1cu/in piston will for the piston forward at a 12.56" stroke this is where the 23psi is from..
300psi/12.56= 23.8 psi....


Tom

[AlanA]

Hi Tommey,

thanks for you brilliant answer.
Is there a formula to calculate the pressure loss?

Alana

P. S.: To come back to the calculation in your former posting:

I have not understand the line in your calculation above:

"having a 4" gear or 4"/2= 2" then we can take 314 psi x 2"= 628 psi or 628/12=52.33 foot pounds"

what means the /12 in the calculation?