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Overunity Machines Forum



STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

Started by PaulLowrance, December 04, 2009, 09:13:07 AM

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0 Members and 26 Guests are viewing this topic.

plengo

Quote from: MileHigh on December 22, 2009, 12:59:04 AM
Freezer:

You can't just "pluck 'radiant energy' out of thin air" to advance your argument.  Sean says that more power is being returned to the battery by the return wire that connects to the battery.

Actually I did do the experiments.  I made the measurements that show that the energy in a pulse discharge from an inductor is less than or nearly equal to the battery energy that energized the inductor in the first place.  That means that Bedini's "radiant energy" is B.S.  I read his 1984 "Kromrey Convertor" 15-page treatise and I almost puked from how little sense he made when discussing electricity and batteries.

So why don't YOU do the experiments.  Hook up any Bedini motor or Joule Thief or whatever your favourite flavour of pulsing inductor circuit you want and measure the power supplied by the battery compared to the power you get from the pulsing inductor.  In all cases you will find the output power is less than the input power, and you produce heat.  The output power plus the heat will equal the input power.  "Radiant energy" is just a buzz word to get you excited and induce you to believe in something that's not there.  You can prove for yourself that it is not there if you really want to.

MileHigh

While you say the BEMF is less or close to equal to source energy that energize the coil is obvious, Bedini says that too.

Bedini clearly states in his forums at yahoo group and videos that there is NOTHING special about his SSGs and motors except that the "magic" happens in the battery. He states that the front end (the circuits) are totally common EE concepts but there is also some anoumalies presented but the battery is the OU creator.

One can easily test the load and charge process and see that there is not enough current going into the battery that could explain the charge being presented. Also the battery capacity increases with time. I know because I have done it over 200 times and it is thruth.

I would think if you tested his motors you should know that!

Fausto.

gravityblock

Quote from: IceStorm on December 22, 2009, 12:54:54 PM


I sound like you like to mix thing but look at your question you asked me :

My answer is still the same, NO , a coil is not a load because the reactive power is equal to the apparent power with a sine wave input so the true power will always be 0W IF its a ideal inductor, like i said in real world there always loss with the inductor since the wire is not a superconductor. Don't mix thing , i don't talk about motor i talk about inductor, your question is "IS A COIL A LOAD?". Do i need to past the link again so you can understand what we talk about again ? http://www.allaboutcircuits.com/vol_2/chpt_11/2.html

Best Regards,
IceStorm

You know in the examples I gave you that the coils would be expending energy in order to generate mechanical motion, thus a load.  You can't obtain mechanical energy without converting the electrical energy.  Even at an idle speed, the battery is losing quite a bit of energy due to the CEMF above and beyond the losses due to the resistance of the wire .

ENERGY AND POWER ARE NOT THE SAME THING.
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

PaulLowrance

Quote from: powercat on December 22, 2009, 12:05:43 PM
From TK
hmmmtoroid_4c
http://www.youtube.com/watch?v=1yurZxrKkeo

Thanks. That's about the only TK video I've seen that's void of strong skeptic opinions while containing useful data.

Anyhow, that effect is easily seen in FEMM.

IceStorm

Quote from: gravityblock on December 22, 2009, 01:08:09 PM
You know in the examples I gave you that the coils would be expending energy in order to generate mechanical motion, thus a load.  You can't obtain mechanical energy without converting the electrical energy.  Even at an idle speed, the battery is losing quite a bit of energy due to the CEMF above and beyond the losses due to the resistance of the wire .

ENERGY AND POWER ARE NOT THE SAME THING!, so go take your power factor and through it out the window, because it is irrelevant in the examples I mentioned.

I told you to look at the rotoverter, there people who get same idle speed , 200/300 watt input at idle  become 15/20 watt for the same idle speed, you just need to change the power factor, THERE plenty of example all around the web, just ask Ash , he is a expert in that field. But we are not talking about TORQUE here , we talk about idle RPM as you said in your first post.So what is irrelevant is you comparison of 2 motor with NO LOAD on the shaft who mean ABSOLUTELY nothing about the torque it can give. What is important is the torque it can give for X power input, that's all , stop wasting your time with your idle speed comparison. you asked me a question to know if a coil is a LOAD and now you move onto something else loll at least i took time to answer both.

Best Regards,
IceStorm

gravityblock

Quote from: IceStorm on December 22, 2009, 01:23:03 PM
I told you to look at the rotoverter, there people who get same idle speed , 200/300 watt input at idle  become 15/20 watt for the same idle speed, you just need to change the power factor, THERE plenty of example all around the web, just ask Ash , he is a expert in that field. But we are not talking about TORQUE here , we talk about idle RPM as you said in your first post.So what is irrelevant is you comparison of 2 motor with NO LOAD on the shaft who mean ABSOLUTELY nothing about the torque it can give. What is important is the torque it can give for X power input, that's all , stop wasting your time with your idle speed comparison. you asked me a question to know if a coil is a LOAD and now you move onto something else loll at least i took time to answer both.

Best Regards,
IceStorm

I never said anything about Power or torque in my example.  I also never said the motors in my example were rotoverters.  My example was meant to figure out how long it would take a battery to discharge in a controlled experiment at a certain RPM.  It is the same as putting a resistor on a fully charged cap and seeing how long it takes to discharge across the resistor.  My example is a good way to figure out how much energy is in the battery so you can make a mechanical comparison instead of an electrical comparison.  Obviously you missed the entire point.  It is possible to have mechanical OU without having electrical OU.  If this is the case, then there may be methods and techniques to convert this mechanical OU into electrical OU or to improve upon the already electrical OU.  My method would be a good indicator if it is achieving its maximum electrical potential and if not, by how much it could possibly be improved upon.  Everyone focuses on electrical OU and forgets about mechanical OU.  You can have mechanical OU and still not be able to recharge a battery or capacitor if this additional mechanical energy isn't converted to electrical energy.

GB
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.