STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[Omega_0]

I meant, I could not understand why this is happening. It seems the inductance is increasing when the magnet is near. Which means rotor does have some kind of effect on the input.

[neptune]

Here are some ideas for a self runner. Someone showed a motor based on a bicycle wheel. Why not use a wheel with a "hub dynamo " These dynamos have few losses , and are actually 12 pole alternators which work at very low RPM ,and give 6 volts at 0.5 amp , or 3 watts. There is hardly any drag . little cogging , and are as efficient as you will get with conventional tech . You will need a bridge rectifier with low loss diodes . I would recomend mechanical switching a described by Omega O on page59 .The advantage of mechanical switching is that eliminates transistor losses. You will need to rectify the output , as due to the high inductance of the toroids , they will not act fast enough for AC to work .

[broli]

I meant, I could not understand why this is happening. It seems the inductance is increasing when the magnet is near. Which means rotor does have some kind of effect on the input.

You are right.

Conceptually there are 3 different cases that can occur. They all have to do with the saturation of the core.

1) When the coil field and magnet field combined are way above the saturation point of core
2) When the coil field and magnet field combined are on the border of saturation level of core
3) When the coil field and magnet field combined are under saturation level of core

As far as my logic goes only case 3 would produce no changing inductance and thus no weird emfs. The distance from the core to the magnet dictates in which case you fall. But Steorn said they also recovered more inductive energy. This would mean that they used the low inductance as a way to quickly charge the coil up and then having the inductance increase quickly by a 1000 fold or more as the magnet moves away. The same current now will have much higher inductive energy in the coil since Eneergy=L*I^2. This is assuming no backemf is seen. I proposed a simple test for this which noone seemed to care about.

[Omnibus]

The most urgent thing to do regarding this motor is to get hold of the current (I) and voltage (U) data from the screen of the scope shown on the 19th of December as well as the value of the Ohmic resistance R. Once these data are dumped into an Excel spreadsheet one can at once calculate the point by point IU product, sum those products up (integrate) to get the input energy and the I^2R (where I is the mean current value) to get the output Joule heat. The device will be OU is

IU(input) = I^2R(output)

That will give us the definitive, unequivocal answer as to whether or not we're dealing here with an oveunity device. If the above equality indeed holds there will not be a single qualified critic in the world who won't find himself silenced by that fact.

Therefore, if there are people on this board who are in contact with Sean McCarthy, please kindly ask him to provide these data (upload them here, for instance). It shouldn't be difficult at all because the data from his December 19th demo are still in his scope and the Ohmic resistance of the toroids (if it isn't known already) can be measured right away on that same demo device which supposedly is still in the Waterways Centre, Dublin.

[plengo]

You are right.

Conceptually there are 3 different cases that can occur. They all have to do with the saturation of the core.

1) When the coil field and magnet field combined are way above the saturation point of core
2) When the coil field and magnet field combined are on the border of saturation level of core
3) When the coil field and magnet field combined are under saturation level of core

As far as my logic goes only case 3 would produce no changing inductance and thus no weird emfs. The distance from the core to the magnet dictates in which case you fall. But Steorn said they also recovered more inductive energy. This would mean that they used the low inductance as a way to quickly charge the coil up and then having the inductance increase quickly by a 1000 fold or more as the magnet moves away. The same current now will have much higher inductive energy in the coil since Eneergy=L*I^2. This is assuming no backemf is seen. I proposed a simple test for this which noone seemed to care about.

broli,

and what that test would be please?

Fausto.