magnet-gravity wheel

[FreeEnergy]

maybe while the arms are switching sides do to gravity it can produce energy to turn off/on the magnetic field with some circuit work.
*make it a one way wheel so when the magnetic field is turned off/on the wheel won't role back?

[Omnibus]

So Magnet atraction force has to be bigger than weight of the arm B in order to flip over the rotor.

This is at the moment shown in the picture. This is before flipping over the rotor. This is just the beginning.

Suppose the magnet is so strong that it starts attracting plate A (countering the weight of the left-hand side).

At the very first moment of attracting A the top begins tilting and the upper plate C slides spontaneously under the action of gravity. It pushes so hard that adds to the attraction of the magnet and pushes plate A beyond the sticky point.

When that point is passed over arm A is atracted by the other side of the magnet which B doesn't.

So the weight of C that now have moved to the outside of the rotor, has to be able to over come the atraction force of the arm A.

It does. It overcomes it.

So if arm B and arm C are the same weight, were the force to overcome this sticky post comes from?

Well, plates B and C have the same weight but C has also kinetic energy. Also B is beginning to shorten the lever arm while C is fully extended and is already starting to feel the pull of the magnet.

[_GonZo_]

plate C slides spontaneously under the action of gravity. It pushes so hard that adds to the attraction of the magnet and pushes plate A beyond the sticky point.

Remenber Plate B is moving at the same time as plate C so the inercial push of C is counter acted by the inercial push of B.

It does. It overcomes it.

Why, do not tell us it does... please tell us why and how.

Well, plates B and C have the same weight but C has also kinetic energy. Also B is beginning to shorten the lever arm while C is fully extended and is already starting to feel the pull of the magnet.

A wheel has no inertial energy unless it is turning and still there is not any force that makes it turns as it is in equilibrium.
If B and C are equal they will move at the same time if well constructed.
So if C is receiving atraction B is receiving it as well...

[_GonZo_]

plate C slides spontaneously under the action of gravity. It pushes so hard that adds to the attraction of the magnet and pushes plate A beyond the sticky point.

Remenber Plate B is moving at the same time as plate C so the inercial push of C is counter acted by the inercial push of B.

It does. It overcomes it.

Why, do not tell us it does... please tell us why and how.

Well, plates B and C have the same weight but C has also kinetic energy. Also B is beginning to shorten the lever arm while C is fully extended and is already starting to feel the pull of the magnet.

A wheel has no inertial energy unless it is turning and still there is not any force that makes it turns as it is in equilibrium.
If B and C are equal they will move at the same time if well constructed.
So if C is receiving atraction B is receiving it as well...

[Omnibus]

Remenber Plate B is moving at the same time as plate C so the inercial push of C is counter acted by the inercial push of B.

Not in the same measure. Plate C is extending itself while plate B is shortening the arm.

Why, do not tell us it does... please tell us why and how.

Construction allows for it. Remember the kinetic energy of C, C already feeling the pull of the magnet etc.

A wheel has no inertial energy unless it is turning and still there is not any force that makes it turns as it is in equilibrium.
If B and C are equal they will move at the same time if well constructed.
So if C is receiving atraction B is receiving it as well...

On the contrary, as said, when starting at the position as in the picture, the magnet pulls A and the rotor starts turning. It?s not in equilibrium.

Also, as said, B and C are not equal. They differ in configuration, in kinetic energy and in experiencing magnetic pull. In this respect C has advantage over B.