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Overunity Machines Forum



6 volts DC in 130 volts AC out simple generator

Started by magnetman12003, April 01, 2010, 04:41:06 PM

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magnetman12003

April 01, 2010, 04:41:06 PM
The below link shows and tells all.

http://www.youtube.com/watch?v=fO9GhHvWGJA

Tom

IceStorm

#1
April 02, 2010, 12:40:21 AM
Quote from: magnetman12003 on April 01, 2010, 04:41:06 PM
The below link shows and tells all.

http://www.youtube.com/watch?v=fO9GhHvWGJA

Tom

lol , alot to learn in electronic, take your time, you will finally understand the basic of the basic. :) . Begin with Ohm law and after that delete your video.

Bruce_TPU

#2
April 02, 2010, 03:17:28 AM
Quote from: magnetman12003 on April 01, 2010, 04:41:06 PM
The below link shows and tells all.

http://www.youtube.com/watch?v=fO9GhHvWGJA

Tom

Hi Tom,

I have been following your work on youtube, very nicely done!

I would suggest, taking some very fast diodes and building a rectifier for the output, rectify it to dc, put it across a resistor and take a current measurment.  I am very curious to see where it stands...  If it is not OU, it in no way diminishes your work, you just keep being creative as you have been and push the envelope...

Cheers,

Bruce
1.  Lindsay's Stack TPU Posted Picture.  All Wound CCW  Collectors three turns and HORIZONTAL, not vertical.

2.  3 Tube amps, sending three frequency's, each having two signals, one in-phase & one inverted 180 deg, opposing signals in each collector (via control wires). 

3.  Collector is Magnetic Loop Antenna, made of lamp chord wire, wound flat.  Inside loop is antenna, outside loop is for output.  First collector is tuned via tuned tank, to the fundamental.  Second collector is tuned tank to the second harmonic (component).  Third collector is tuned tank to the third harmonic (component)  Frequency is determined by taking the circumference frequency, reducing the size by .88 inches.  Divide this frequency by 1000, and you have your second harmonic.  Divide this by 2 and you have your fundamental.  Multiply that by 3 and you have your third harmonic component.  Tune the collectors to each of these.  Input the fundamental and two modulation frequencies, made to create replicas of the fundamental, second harmonic and the third.

4.  The three frequency's circulating in the collectors, both in phase and inverted, begin to create hundreds of thousands of created frequency's, via intermodulation, that subtract to the fundamental and its harmonics.  This is called "Catalyst".

5.  The three AC PURE sine signals, travel through the amplification stage, Nonlinear, producing the second harmonic and third.  (distortion)

6.  These signals then travel the control coils, are rectified by a full wave bridge, and then sent into the output outer loop as all positive pulsed DC.  This then becomes the output and "collects" the current.

P.S.  The Kicks are harmonic distortion with passive intermodulation.  Can't see it without a spectrum analyzer, normally unless trained to see it on a scope.

Low-Q

#3
April 03, 2010, 12:44:43 PM
Quote from: magnetman12003 on April 01, 2010, 04:41:06 PM
The below link shows and tells all.

http://www.a.com/watch?v=fO9GhHvWGJA

Tom
It actually it doesent tell a thing. Volt isn't energy itself. It's in theory no problem in generating several gigavolts out of a 1.5VAAA battery. The question is how much current it can carry. The output product of "current x voltage" cannot exceed the input product of "current x voltage".
That means that you will have a current drop as the voltage raises. And visa versa.

Vidar

magnetman12003

#4
April 03, 2010, 08:41:19 PM
[A author=Bruce_TPU link=topic=8990.msg235870#msg235870 date=1270192648]
Hi Tom,

I have been following your work on youtube, very nicely done!

I would suggest, taking some very fast diodes and building a rectifier for the output, rectify it to dc, put it across a resistor and take a current measurment.  I am very curious to see where it stands...  If it is not OU, it in no way diminishes your work, you just keep being creative as you have been and push the envelope...

Cheers,

Bruce
[/quote] Hi Bruce,

Hi Bruce,
Thanks for your comment.  I will take your advice and do just that. I bought a true RMS multimeter and am waiting for its arrival.   I always did wonder what kind of power output a spinning magnet under a load would have when spun by low DC  voltage and current.  I am having fun never the less.
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