GENERATOR- YOU DO THE IN/OUT POWER MATH

[Rapadura]

Input : 1.6328W

Output : 4.2W

COP = 2.57

Wow! I love COP greater than 2! Because it's not over-unity, it's over-double!

If a generator can really put out COP > 2 then this generator can power itself (self-running), and, at the same time, can power another generator that is exactly equal the first one. And this second generator will also put out COP > 2, then this second generator can power TWO more generators exactly equal the first two. And this two new generators can power FOUR more generators equal the previous four.

Then you will have:

INPUT = Nothing. Zero. Just a self-running generator.

OUTPUT = Four generators exactly equal the first self-running generator.

That's why I have dreams with "over-double" every night! Over-double rulez!

[DeepCut]

Tom,  I'm no expert here and I'm sure mscoffman knows more than me but it seems if you are going to try for a self runner you'll lose a lot of efficiency with the way he is suggesting.  So I'll suggest a different way and if others see a flaw with my suggestion that's fine as I said I know mscoffman and others here are way more up to speed on this than I am. 
  I'd suggest simply stepping down the voltage from your output with a small transformer that has about 4:1 ratio and then rectifying the output and feeding that to the input - maybe a filter cap on the rectified output too?  At least to me it sounds like it would be a lot less losses that way.

Funny, i just tried that.

I made a small coil to step down the voltage and see what current increase i could get.

The voltage went  w a y  down to around 6V and the current doubled to 250mA but the magnet slowed right down.

Obviously it's not a proper transformer because there's no physically connected ferrite-core ...

[mscoffman]

The thing about the adjustable load resistor is...in all probability
the behavior of the motor is going to change as you load it down
because you apply mag braking force to it, which is what happens
when work is extracted...So adjusting to maximize the Power will
affect the operation of the device and hence feedback to the input
power required. Now, that feedback may require more input power
(which it would in a typical motor), or it might require less -
because slowing the rotor will force the drive "on" periods apart.

So once you have the design working you have to shift your goals
to maximum power output of a calculated P rather than your inital
design goals to maxize rotor RPM.

You really want to measure both Power(s) at the exactly the same
time. A DVM won't load the voltage (with many megohms meter input
impedence, but the mechanical voltmeter will) And unfortunately the
current ranges will not have nearly the theoretical zero ohms insertion
loss that it should. But generally the resistance of the load resistor
won't change with use...So that is one thing that remains constant.

By finding the matching impedance you find out something useful about
how to design the load utilization circuit. Listen, a diode bridge *will*
wring out most usable power out of even spiked AC signals but
impedance matching (making your voltage converter the same impedance)
as the maximum power point load) is somewhat tricky. Do it wrong and you
risk getting unnecessary ineffciency in the power loop. The ability to build
a pulse transformer built like the JT torroid would be a good capability to
have because a good transformer automatically keeps the E and I terms
of the P=E*I in the same ratio. So you want to step the pulse AC signal
down and then rectify it. Filter it with a big cap. The 12VDC inverter
110/220V may be inefficient but it will help stablize your feedback loop.
It's input power will very much be a function of it's output demand. A
motor COP 2.0 is usable if the inverter has a efficiency of 50% - a nice
experimental capability to have, and hold on to.

BTW in the real Overunity device the power is going to build up, then you
will need a way of disposing of it properly...Also a nice problem to have.

:S:MarkSCoffman

[DeepCut]

Nice one Mark

One thing that i feel the need to understand, why can my analogue meter read the mA but my digi can't ?

My digi even goes down to micro-amps, unlike the analogue, but still registers nothing ...


Gary.

[mscoffman]

Nice one Mark

One thing that i feel the need to understand, why can my analogue meter read the mA but my digi can't ?

My digi even goes down to micro-amps, unlike the analogue, but still registers nothing ...


Gary.

You say you have replaced the fuse, That fuse may have more resistance
than the original, the pass resister inside the meter could be burnt,
changing it's resistance or something inside the meter's IC could be damaged.

:S:MarkSCoffman