The Gabriel Device, possible COP=8

[FatBird]

For those that don't know, Kill-A-Watt meters measure

Volts, Amps, Watts, Hertz, Power Factor, & KWH (Killawatt Hours).


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[Feynman]

The original Toroid I had made was for rodin coil experiments, thats why it looks like it does, but for this experiment I needed more room to feed wire on to the primary, the last variation when I cut out 1 inch allowed me to put on extra wire but I still ran out of room, so I took out another inch so we can get the necessary wire placed on to the primary.

Okay, thanks, that answers my question.

As far as L&S I called them and told them to source out the part you will be getting the new piece I had retooled, because this shell isn't optimal. the only nice thing about having such a large gap in the center is it allows the inside parts to breath a bit. but we can do the same with the new part if need be.

Okay sounds good.  I suppose we can always add a CPU fan if there are eddy current losses in the steel and it heats up. 

[Feynman]

Hello Mavendex
As a test you can calculate the value of a capacitor and put it in parallel with the coil. The reactance of the capacitor should remove the reactive power drain portion of the total power measured by the "Kill-O-Watt" meter.

Allright I'm gonna put my ignorance on full display here.

Calculating the value of the capacitor:
Measure the voltage drop across the toaster.

How do you suggest one does that?   By measuring the impedance of the toaster, and then calculate the voltage drop as E = IZ, where I is toaster current consumption , and Z is toaster impedance?   This may suffer from the problem , as the toaster current consumption / resistance is probably temperature dependent if it's anything like a conventional light bulb.

Measure the current in the circuit.

With conventional DMM in series with the toaster while powered on?  Isn't this prone to the same error that you objected to in the first place (amp meters being 'tricked' by inductive reactance?)  The toaster current might be time-variant even without the primary.

Using a conventional DMM Calculate power used by toaster P=IV. Subtract the toaster power (P) from the power (S) measured by the "Kill-O-Watt" meter.

So here you would use the E value calculated previously for the voltage drop for V, and you would use the current you measured previously for I just for just the powered-on toaster in isolation?

Whats left is the reactive power (Q) drawn by the coil from the power supply. BTW cosÓ¨ = P/S (Power factor of the circuit )

Okay.

The reactance (Xc) of the required capacitor is
Xc = V²/Q   V = mains power voltage

Okay.  What material capacitor is preferable?

C = 1/(ωXc) where ω = 2πf (f = frequency of mains) This should give you an approximate value for a capacitor to try.

Okay that's a PI value not an 'n' just to clarify for the record.

Now when you draw power from the second "Kill-O-Watt" meter, the first meter should indicate an increase in power consumption. If it does not then you have a possibility of an over unity device.

Okay, thanks.  This is pretty complicated and is beyond my understanding, but hopefully we still get COP>1 even if we add the capacitor to the coil. 

[teslaalset]

Just a question on the winding ratio.
At the PesWiKi website I noticed that the around 300 feet of wire is used for the secondary (inner) coil and 400 feet for the primary (outer) coil.
It seems that because of the diameter difference between primary and secondary coil, the winding ratio is far from 1:1.
I would estimate it around prim:sec = 1:10.
This means that the voltage at the secondary would be 10 times higher as the input voltage.

So, the diagram of Kampen (reply #65) likely contains some flaws regarding the windings.

Also, mind you, we are probably talking 1kV at the output.
That's probably lethal for those that do not mind.
Is there any measurement data available on the voltages?

[Montec]

Hello
As an addendum to my previous post:

If you know the power factor for an inductive device or circuit then the reactive power (Q) is

Q = S x sin(cos^-1(power factor)) where S is the power in VA (volt amps) measured by the watt meter.

Just for information:

S (apparent power) is measured in VA (volt amps)

P (real power) is measured in W (watts) This power is able to do work.

Q (reactive power) is measured in "vars" (quadrature "imaginary" power)

So S² = P² + Q²