Hydro Differential pressure exchange over unity system.

[Gwandau]

MileHigh,

thanks for the response.

So even if the amount of water displaced by the right cylinder is less than the left cylinder, there will no difference in lift?
Excuse me for my ignorance, I always thought the Archimedes principle was depending on the displaced amount of fluid in relation to the weight
of the displacing object.

Gwandau

[MileHigh]

Gwandau:

In your example the fixed inner cylinder on the right could just as easily have been air and it would be the same thing and act the same way.

The real cause of the buoyancy is the air pressure pushing against the inside of the outer cylinder.  All of the air pressure pushing on the vertical walls of the outer cylinder provides no buoyancy because the air pressure is in a horizontal direction and it all cancels itself out.  The only thing that counts is the air pressure that pushes on the top of the inside of the outer cylinder.  That air pressure comes from the water pressure at the bottom of the tank.

You just have to look at the individual surfaces and the forces on those surfaces from the air pressure or the water pressure.  In the case of the setup on the right, the water pressure at the bottom of the tank becomes the air pressure inside the outer cylinder.

MileHigh

[MileHigh]

I always thought the Archimedes principle was depending on the displaced amount of fluid in relation to the weight
of the displacing object.

This is a specific example that is simplified.  If you were to look at it in terms of surfaces and the water pressures and air pressures on each surface you will arrive at the same conclusion as the simplified example.

[Gwandau]

MileHigh and seamus102,

thank you for enlightening me, your descriptions were clear and elucidating.

regards,
Gwandau

[mrwayne]

Well... that's fair enough, because honestly, I don't yet understand your explanations, either.

So...let's try it like this.

Do you have a single Zed, that shows the effect, the gain, the overunity, by lifting a known weight a certain distance, or providing a known volume output of liquid at a known pressure?
(This can be answered YES, or NO.)
If NO... then stop, because we have hit a contradiction: I think that earlier you (or someone) said that you did.

If the answer is YES.... then, does it start out,  motionless, at a position with pressures and volumes known, and wind back up at that same position, with the same pressures and volumes?
(Another YES or NO answer can be given.)
If NO... then stop, because we have hit a contradiction: we have not yet completed a CYCLE.

If the answer is YES.... then, what does it take to start it up and make it lift that known weight that certain distance, to the top of the cycle?

The answer to this last one I expect to be something like "We need to push down (or in) on a hydraulic ram" or "We inject a volume of liquid at a pressure" or something like that. Very simple.

OK, I have tried to make it easy for you to understand my questions so far. Will you please try to make it easy for me to understand your answers?

Once I understand the answers to this part, I might be able to understand the rest. You have to cut me a little slack, though... I am straitjacketed by my education and it takes me a little while to wriggle out of what I "think" I already know.

TK, I have a great deal of respect for you and the effort you have given to help and protect others
I said I will answer your questions about energy -
Be clear - I do not share on this site to try to convince anyone or to replace the "team in place" for our validation.
Your format is inappropriate for my stated and intended purpose here.
I will repeat what I have said - our current single unit is barely better than a hydraulic cylinder - you can measure the input and output  - we do not use weight - but volume and pressure. Yes - our three layer system is clearly overunity by itself.
In this small model - hooking the system together bumps us up by reducing the input further.
Oops dinner - more later.
Wayne