Hydro Differential pressure exchange over unity system.

[mrwayne]

No offense taken,
I am impressed with the hose anology - you caught on - I told that last year-
I have learned that jumping to the end gets me know where (educating wise)
This system requires more insight than most are willing to afford.
Look at this -

[neptune]

OK I will agree with the figures, but not sure about the formula . I remember from school that pressure = depth times density . The diagram shows 4 columns of water each 12 feet high . So we know that pressure is directly proportional to depth . An equivalent diagram would be a single pipe, 48 feet tall with pressure guages every 12 feet . We know that atmospheric pressure can support a column of water 30 feet in height . [ the limit you can lift water by a suction pump is 30 feet .]  So I would expect the pressure at the bottom of a 48 foot column to be about 24 pounds/ sq inch . The formula is this . The pressure at any point in the system is Inlet pressure minus 0.43 x total height of water columns between inlet and measurement point. This formula does not quite work exactly.

I asume your diagram represents a hose so the volume in each column is the same . This will not be true in a ZED unless inter cylinder gaps are adjusted to compensate .
 
I have said twice previously that we must start at the beginning, so "jumping to the end" will cause problems.,

[mrwayne]

I asume your diagram represents a hose so the volume in each column is the same . This will not be true in a ZED unless inter cylinder gaps are adjusted to compensate .
 

Bingo!
That is what we refer to as set up - that is the only air put in the system - once..... Make sense now?
A lot of people got hung up on that single point.
Thanks
Wayne

[neptune]

Thanks mrwayne. Was my formula anywhere near correct, please?


Ok so now we have 4 reservoirs of compressed air . We have switched off the compressor used for initial charge, disconnected it and closed the inlet port . The air pressure in said reservoirs is 5 , 11 , 17 , and 22 psi.
So now we allow the risers to rise . Its a bit like a compound steam engine in that we have different size pistons for different pressures ? And each riser or piston produces the same thrust ? I will say no more until and unless I get confirmation of what I have said . Many thanks.

[mrwayne]

Dear Seamus,
You are right - I do not talk in your language, I am afraid - if I did - I would probably see as you - you imply for this reason - that I am inferior - I have no reason to be concerned by your opinion.
I would never think to place myself above you.
I do not question your ability,  just that your conclusions are extremely premature to your understanding of the system.
You demonstrate you do not understand the system by your comments thus far, many start out that way.
I do undertand our system, very well - I do not insult you for being wrong.
I have asked you for "nothing"
Nor did I ask your opinion - I just welcomed questions.
Thank you,
Wayne Travis