Hydro Differential pressure exchange over unity system.

[telecom]

If there is a serious builder out there who understands the challenges and the concept...  Yes, by all means I will CAD.

Just to let you know my "vision" of this project, I was hoping to do a complete miniature replication of the existing ZED test setup.  But I can deviate from that idea to help others.

In my vision we would end up with the two ZEDs and the water transfer system.  The transfer system could be made from bellows type vacuum cups like the below, once they were properly attached to a surface to turn them into a pressure type pump.  How to actuate that pump system (ie. collect output from the system and reuse) is still a problem in miniature.  And the controlls...

But others may have ideas?

Hi mondrasek,
I think we need to come with exact sequence of the operation of the machine first.
Perhaps you and Larry C. understand it - may be you could share your knowledge?
Alex

[mondrasek]

@telecom,

I'd be happy to try and explain the exact sequence of operation of the machine if I only knew what was unclear.  The patent spells everything out very clearly to me, but I understand that is not the case for everyone.  Playing with the drawings I have made and the calculations have also firmed up some things for me.  Maybe if you had some specific questions?

Maybe the picture below is a good start.  The ZED on the left has no lift.  The ZED on the right has full lift and has stroked to it's mechanical limits.  So from this starting point the pressurized water at the bottom of the center chambers would be allowed to flow from the right ZED to the left ZED freely through the pipe shown.  Once half the water has been redistributed the system reaches a balance and both sides are at the same water pressure.  Now the pump (circle in the drawing) would begin to pump the second half of the water from the right ZED to the left ZED.  While this second half of the water transfer is happening, the left ZED will become buoyant and begin to rise.  At the same time, the right ZED will have lost it's buoyancy and begin to sink.  When all the water has been transferred, you have the mirror image of the picture below.

M.

[mrwayne]

Just something that should help you understand what is going on (I have posted it on PESN as well):

Hello again Kanshi,

I will be glad when you understand the system.

Wayne

[mrwayne]

I hope people will now see this for the trick it is.  Because the stored energy oscillates between the two Zeds it creates the illusion of energy being created because it will remain in motion for quite a long time. The internal flows are quite slow, so the internal losses will be too.

Seamus,

It is no trick, no fraud, no lie, no error, no mismeasurement.

We do not have a system that just "stays in motion" we have a system that Produces its own operating energy and supplies extra.

Even the first engineers wrote - enough to supply  consumer end power.

Wayne

[TinselKoala]

@telecom,

I'd be happy to try and explain the exact sequence of operation of the machine if I only knew what was unclear.  The patent spells everything out very clearly to me, but I understand that is not the case for everyone.  Playing with the drawings I have made and the calculations have also firmed up some things for me.  Maybe if you had some specific questions?

Maybe the picture below is a good start.  The ZED on the left has no lift.  The ZED on the right has full lift and has stroked to it's mechanical limits.  So from this starting point the pressurized water at the bottom of the center chambers would be allowed to flow from the right ZED to the left ZED freely through the pipe shown.  Once half the water has been redistributed the system reaches a balance and both sides are at the same water pressure.  Now the pump (circle in the drawing) would begin to pump the second half of the water from the right ZED to the left ZED.  While this second half of the water transfer is happening, the left ZED will become buoyant and begin to rise.  At the same time, the right ZED will have lost it's buoyancy and begin to sink.  When all the water has been transferred, you have the mirror image of the picture below.

M.

Stevin's Principle.