Hydro Differential pressure exchange over unity system.

[mrwayne]

     

@telecom,

I'd be happy to try and explain the exact sequence of operation of the machine if I only knew what was unclear.  The patent spells everything out very clearly to me, but I understand that is not the case for everyone.  Playing with the drawings I have made and the calculations have also firmed up some things for me.  Maybe if you had some specific questions?

Maybe the picture below is a good start.  The ZED on the left has no lift.  The ZED on the right has full lift and has stroked to it's mechanical limits.  So from this starting point the pressurized water at the bottom of the center chambers would be allowed to flow from the right ZED to the left ZED freely through the pipe shown.  Once half the water has been redistributed the system reaches a balance and both sides are at the same water pressure.  Now the pump (circle in the drawing) would begin to pump the second half of the water from the right ZED to the left ZED.  While this second half of the water transfer is happening, the left ZED will become buoyant and begin to rise.  At the same time, the right ZED will have lost it's buoyancy and begin to sink.  When all the water has been transferred, you have the mirror image of the picture below.

M.

I am stuck at the air port - nine hour wait.

The two Zed system is not connected as drawn above - the water in the pod section is always under pressure - the pressure is related to the direction of travel and stage of the process.

When Zed 1 is all the way up - it has the full charge in Head + the volume inside the pod added for stroke length- It is at the top because it has just finished its production stroke -

At this moment the Hydraulic assist is "on" but no movement or consumption of energy. - To be clear - the hydraulic assist is what adds to the head pressure from the lowering Zed in order to overcome the hydraulic resistance in the production cylinder - or the load.
 

Both Zeds are connected to opposite sides of one a piston (bags in our lastmodel) that piston is at the end of its travel or near empty at zed one.

Zed one
is at Its has the highest presssure (8 psi - example given last week)

Recap Zed one - top of stroke - high pressure connected to Mass exchanger --(bags - cylinder)

The other Zed (Zed Two) is at the bottom of the stroke It still has 4.6 psi (caused by the weight)

Now the first step is to let go of the hydraulic assist - The two Zed's eqaulize head pressure - so both heads are now at 6.7 psi --both zeds are still in the same position they were in - but the Mass exchanger has traveled half of its distance.

Zed two is ready to be precharged - this means going from 6.7 psi to 8.0 psi (over coming resistance pressure).

The precharge is nearly instant - when the first hydraulic assist is turned on - when the pressure drops to 4.6 psi - about 3/4 of the total travel - we kick on the second hydraulic assist cylnder.

And we finish the stroke (we are capturing the buoyancy during the Stroke.

Then we are half way through a cycle - Zed two is up (8psi) and Zed one is down (4.6 psi)

ready for free flow to begin - the other direction.

Let me be clear - we exchange 1/2 of the hydro transfer during free flow - no input - then we pay for 1/3 of the next quarter, and then less than half of the last 1/4 .

That is our total input - nothing else - very simple.

The layering system which Kanshi disregarded - makes the "Exhaust or water transfer" pay for nearly 70% of the total input cost for each Zeds production stroke (roughly - three layers - better with more layers).

When our third part engineers measured the up stroke - they were excited - but when they realized that alll the energy for the up stroke was available for the transfer - (minus standard losses)

The weight in the system reduces the ideal of the unit - but do not mistake ideal for effeciency, yet the weight makes the transfer more powerful - and the size of the weight (percentage of ideal) is based on th enmber of layers.

So when you see th ethree layer system has about 1/3 of its ideal lifting weight - now you know.

A point many critics make is to ignore that stored energy in the head - still complete and intact - at the end of every a stroke.

Wayne Travis

can't spell check on this cp - sorry

[LarryC]

I've improved the spreadsheet to make it easier to understand. Also, got rid of the confusing PSI not being equal to the head. Anyone who understands Wayne's earlier post of the forces in holding a cup full of water underwater and a cup of air underwater should understand the spreadsheet.

This was just to make M happy. LOL
Good luck with your trip, Wayne.

Regards, Larry

PS: A Riser is a cup.

[mondrasek]

This was just to make M happy. LOL

And you have achieved that (noble) goal!

BTW, you can use "PI()" to return a much more precise version of "pi" in your calculations rather than typing in the 3.14... figure.  That would make me even happier.

Much thanks, Larry,

M.

[LarryC]

And you have achieved that (noble) goal!

BTW, you can use "PI()" to return a much more precise version of "pi" in your calculations rather than typing in the 3.14... figure.  That would make me even happier.

Much thanks, Larry,

M.

So, 4 decimal positions is not accurate enough, are all engineers such precision fanatics?

@All,
The Wayne example I referred to in my previous post is Reply 108 on page 8.

Regards, Larry

[mondrasek]

So, 4 decimal positions is not accurate enough, are all engineers such precision fanatics?

As my wife may tell you:  Only the nerdiest.

(sigh)

M.