Hydro Differential pressure exchange over unity system.

[mondrasek]

Okay, this is stupid, but I could not get it out of my head.  I was stuck at home for a bit anyway and was (again) chuckling to myself about the LED lighting...  Like I have any LEDs!  I don't (except inside working devices).  Or so I thought.

I happened to notice an old 3 LED mini flashlight that I inherited from someone who bought it and said it didn't work.  So a few minutes later and you have the picture below!  And the real beauty of this lighting scheme is the power!  Its an old Toshiba laptop power brick regulated through a DC/DC buck/boost converter.  And even hooked up with alligator test leads.

I hope this cracks you guys up as much as it does me!

Seriously though, I have not made it to the store to get a digital mass scale, so no real testing to be done anyway.

Cheers,

M.

[LarryC]

In your attached drawing, only the first 2 steps can work. How can we use the hydraulic assist to use the lower pressure Zed to pressurize the higher pressure Zed?

Thanks for the question. My statement:
Hydraulic Assist - Since the Zed water columns start equal, the input cost will be to change the actual Water Head between Zed's from 0 to 3.4 PSI

Please see the attached picture. Water weight is .0361 pounds per cubic inch and creates a force of .0361 PSI. Water Head in this case is the difference in height between the two columns of water. The example on the left with the equalized columns has 0 PSI or 0 Water Head. For the example on the right, if the Hydraulic cylinder pushes down the left column 1 inch, this causes the right column to rise 1 inch and the difference is 2 inches or (.0361 * 2) or .0722 PSI or a 2 inch water head. So the Hydraulic cylinder had to use a force that went from 0 PSI to 0.0722 PSI. Because of gravity, your input cost only needs to account for the height difference in the two columns.

Hope this helps. Please excuse for stating facts that you allready know, but others are also learning.

Regards, Larry

[mondrasek]

Test data from previously shown model:

The lift mass is a 2.5lb free weight of unknown accuracy.  The mass is used during the "lift" and then removed during the "sink" portions of a cycle.  There is an unknown preweight that is never removed along with the mass of the Pod and Riser construction as well.

This experiment was run several times to verify that the measurements were at least "close" to prior runs.  But all measuring apparatus are very far from precision instruments.  Also, there is some stiction in the ZED model, but I tried to compensate for that by always loading from the same side (ie. all readings were taken after coming from a lower pressure/height up to the previous alignment marks).

Data (as it is):

Mass lifted:  ~2.5 lbs
ZED stoke: ~ 11.5 mm.
Water removed and introduced again to obtain repeatable(ish) stroke as measured by a "rain gage" from my yard: ~87.5mm.
Overall change in the head in the elevated fill tube during the cycle is ~ 190 mm.

Now I have no idea which (if any) of those measurements I should have skewed higher or lower to prove anything one way or the other, so I think the data is pretty objective.  Please send questions before revealing any results so you don't taint my objectivity.

Let me know what else you want/need for now. 

M.

[neptune]

Here is another of those questions you probably did not know the answer to, but were too embarrassed to ask. Well I am not too embarrassed, and I dont mind being thought of as the village idiot if that makes people happy .


Question. In earlier diagrams of the Zed,we see that the risers are separate items , with an air gap between their tops or lids. But now, Wayne says that we can have all the risers sharing a common lid. { see post1922 on page129 for a diagram . } So now, if we take the outer riser as an example, compressed air was lifting the entire lid of the riser, in early diagrams. But in the later "common lid design" , lift is restricted to a narrow annulus between the outer risers wall, and the wall of the next riser. So how come we get the same lift with a much reduced lift area? the air pressure is the same.


My answer. The air in the gap between the lid of the outer riser and the lid of the next riser. gave extra lift. But this extra lift was cancelled out by that same air pocket pressing downwards on the lid of the next riser.


Anyone agree/disagree?

[see3d]

My answer. The air in the gap between the lid of the outer riser and the lid of the next riser. gave extra lift. But this extra lift was cancelled out by that same air pocket pressing downwards on the lid of the next riser.

Yes, that is right.