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Charging Batteries from Batteries part 2. Free Energy?

Started by dandman, April 19, 2011, 10:21:33 PM

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nightlife

 Again, you must not have understood what I said. I will try a different way

You may show the same voltage but you will not show the same amperage. You must know how many amps are in the charged battery. Once you know that, then charge the other batterys with that battery and find out how many amps they have. I bet you will loose amps. You can not go on volts alone, volts mean nothing if there are no amps. They all may show the same volts and even differ slightly but the amps are what is need to know to know if you have a gain or a loss.

dandman

Dear Nightlife, I get it, I really do. THE WATT IS KING. Voltage to me is only a very unreliable indication of watts or amps as everyone likes to call them, available. I load tested the batteries with a 30amp draw for 15 seconds before, the battery dropped to 10.5v and returned to its original voltage of 12.64. I repeated this after 2 discharges and recharges. Same result. I presume we are talking about my previous post here?.
This post I havent quite got my head around at all yet. Currently waiting for it to run its full cycle before I do any load testing. So far its been running for just over 4 days. Thanks for the input. I am not averse to learning and I do want ppl to pull holes out of these things as I am averse to looking like a prat. grin

nightlife

 Lets try this again. You must know how many amps. I have yet to read how many amps you started with and how many you ended with. Once we know the amps, we then can find out how many watts becuase you have already gave us the volts. Volts X amps = watts.

dandman

Ok, I must be missing something here. Please be patient.
1 amp at 12v = 12w. 1 amp hr at 12v is the constant supply of 12w for an hour. If I start at voltage x and discharge to voltage y for 1 hour at 1 amp. I have discharged 1 amp hour. If I then return the state of charge back to voltage x and discharge to voltage y again for 1 hour at 1 amp. I only us the voltage as a reference point. Is it not true that I must have replaced the 1 amp hour of charge I used back in the battery. Or is there another reading or calculation you would have me do, if so, what?. Thanks

nightlife

 I cant say because we dont have the starting amps and the ending amps. The car battery you have problably has 700 to 1000 amps at 12 volts. You charge another battery with it, you mostlikely will still see the same voltage but with lower amps. The battery that was charged may also show the same voltage but it too may have lower amps. You have to know what the watts are in each battery before and then add them up and then find out the watts in each battery after and then add them up. If the total of the start is lower then the total after, you have a gain, if not, you have a loss. We can't tell you based on the lack of information you have gave us. We have to know how many amps are in them at the start and how many after before we can say wether or not you have a gain or a loss.