Confirming the Delayed Lenz Effect

[gotoluc]

Thane, I was drawing the same conclusion at first glance, but.....
to be dead sure, we need the total primary current, while the primary current that Luc is showing is only the current that is going through the primary coil and not the current through the parallel capacitor, at least that is what I observe from it.
The current through the capacitor should be added as well.

So, Luc can you check whether you connected the parallel capacitor before or after the serial resistor?

Hi teslaalset,

the Capacitor is connected after the series Resistor, directly in Parallel at the Primary Coil.

Thanks for your interest

Luc

[gotoluc]

Thanks for the video gotluc. I have a question though, did the circuit act differently if you shorted it vs using the led. The reason I ask is, don't led's act as diodes? This wouldn't be the same as a short circuit. Now back to watching the video..

Also, you keep saying current changes when it is the voltage isn't it?

Hi Shadesz,

thanks for your interest.

The results are the same if I short the Secondary.

Technically the Green waveform is a Probe measuring the Voltage across a 1 Ohm Resistor that is connected in Series on the Ground of the Signal Generator lead. The Yellow waveform is a Probe measuring the voltage between the Hot lead of the SG and the Ground of the SG. All probe Grounds are connected together on the same side of the resistor which is closest to the SG ground.

From what I understand when a Dual trace Scope is connected in this configuration the Probe connected between the Resistor is a representation of Current being consumed. Also, one can observe Phase Shift.

Please correct me if I am not doing this correctly or miss understanding something.

Luc

[Overunityguide]

Tomorrow I'm going to my storage to pickup some large AC Capacitors. Going to see how far down I can drop the Frequency. It would be nice if I can get it down to 60Hz.

@gotoluc, Great work so far. My compliments, of course when there is only reactive power going to a primary coil you can power factor correct this by putting a parallel capacitor to your primary. But for now please don't forget that when you try to lower your frequency to the 60 Hz you mentioned that you will kill the desired Delayed Lenz effect at your secondary side. So as a result of this I would expect that you cannot run your load purely reactive again. Because if the only important thing to this was primary power factor correction related, than every manufacturer of microwave oven transformers would be doing this.

So my advice is to not go below a certain frequency... lets say not below 700 Hz or something like that...

Please see my videos in where I get totally different results for 200 Hz and for 950 Hz:

Part 1: http://www.youtube.com/watch?v=IbmharDOA3Y
Part 2: http://www.youtube.com/watch?v=2YiRV1SUsgc&feature=related

Keep up the good work, and With Kind Regards, Overunityguide

[teslaalset]

Regarding the LED as a load? it is a diode and gives a near shorting effect in every second half period of the AC wave whenever the LED senses a forward bias from the AC amplitude.

I guess it is a single LED, so, indeed it kind of shorts one half of the cycle.
Because it's shown in resonance, it doesn't show a clear distorted current waveshape (a not symmetric sinus).
Would be interesting to see what happens if there are 2 anti-parallel connected LED's are applied, so both sinus halves periods are performing shorting.
I would expect a more explicit phase shift in that case.

[gyulasun]

I guess it is a single LED, so, indeed it kind of shorts one half of the cycle.
Because it's shown in resonance, it doesn't show a clear distorted current waveshape (a not symmetric sinus).

Would be interesting to see what happens if there are 2 anti-parallel connected LED's are applied, so both sinus halves periods are performing shorting.
I would expect a more explicit phase shift in that case.

Well, I think we have to consider how good the shorting effect is the LED(s) represents with respect to the effect of a real short like a piece of wire?

The green LED needs about 2V forward voltage and assuming a 15mA current for the brightness in Luc's video, this LED represents a loading resistor of 2V/0.015A=133 Ohm, very far from a short circuit case.
By putting two LEDs anti-parallel then both half waves of a cycle would be symmetricall loaded (i.e. clamped) by the LEDs indeed but their loading effect still would be in the one to two hundred Ohm range.

This way I think the phase shift would not change too much either in this respect. So a heavier load (like a few watt incandescent light bulb or even  a few Ohm resistor may represent) is to be used.