Any proof?

[ltseung888]

Lawrence,
Thank you for posting these data. I understand that replication is difficult due to the need for the circuit to be operating at resonant frequency. Forgive me for asking if this has already been explained, but I'm wondering if...
- it might be possible to produce prototypes with a variable resistor or variable
  capacitor to fine-tune each unit to resonance, perhaps with some kind of
  LED or neon which might indicate that the unit has achieved the lead out
  frequency. ...
Again, perhaps this has been already discussed, or maybe it is unfeasable; but I thought I'd ask...
Continued blessings on you and your work.
Bob

Dear Bob,
If you have two oscilloscopes, the tuning is easier than you may expect.  The trick is to set both the Input and Output scales to be the same and observe the change in waveforms â€" especially the Output Power Curve.
You can see a large standing wave when you vary the breadboard positions, resistance, capacitance values or just changing connecting wires.
Once you get that, set your oscilloscope for maximum sensitivity to get the csv files for detailed analysis.
Sometimes you can hit on an exceptionally high COP circuit (or recharging circuit).  Most researchers then keep that confidential for commercial reasons.  They need to earn money and cannot afford to have fun all the time.
My advice is â€" experiment.  Resonance hunting is still an art.  Luck is important too.  But if you try hundreds or thousands of times, luck will come to you. 
Lawrence

*** I added the analysis for the Jan 11 prototype.  It was a slight variation compared with the Jan 16 prototype.  It has COP of 74. 

[SchubertReijiMaigo]

My advice is â€" experiment.  Resonance hunting is still an art.  Luck is important too.  But if you try hundreds or thousands of times, luck will come to you.  Lawrence

Not only a mere resonance but a high Q resonator (high L/C and low R) to have Q > 1...

[pauldude000]

High Q but low Z. Remember that impedance at a given frequency is equivalent to resistance. At resonance, Z should be at a minimum to allow maximum current flow. High Z in effect is like placing a resistor in series.


Edit : should have provided formulas... sorry


Inductive impedance = 2 * Pi * f * L


Inductive capacitance = 1 / (2 * Pi * f * C)


L is in Henries, C  is in Farads, F is in hertz


Instantaneous Voltage and amperage equations: t = time in seconds, v = voltage in volts, and i  = amperage in amps


v = L * (di/dt)     i = C * ( dv/dt)


amount of energy stored:


In the inductance: E = (L* (i squared))/2
In the capacitance: E = (C * (v squared))/2


These you might find useful.

[Bob Smith]

Lawrence,
Thank you for the advice and encouragement.
Bob

[ltseung888]

http://www.overunityresearch.com/index.php?topic=1171.msg20682#msg20682

It looks like Sterling Allan has found a Commercial OU product in South Africa.

I fully expect it to work.  I am attaching an Output vs Input Power file from the latest FLEET tests.
The average Input Power is Negative.  That is a recharging circuit.  Is it OU by itself???

Is that sufficient proof???