Is joule thief circuit gets overunity?

[ltseung888]

http://www.youtube.com/watch?v=Rw-a2BBPqik&feature=youtu.be

Another video to confirm that Input Current (Iin on Ch2) can change from positive to negative value by varying the Input Voltage.

This means that we can vary the COP from 9.6mV to -16mV on Board 80 by increasing the Input Voltage Vrms from 360mV to 1.12V.  The sero Ch2 Vavg occurred when the Input CH1Vrms was at around 440mV.

The experiment can be repeated easily.  Board 80 can be guaranteed to be OU!!!

[Rodelu]

Board 80 can be guaranteed to be OU!!!

[hoptoad]

http://www.youtube.com/watch?v=Rw-a2BBPqik&feature=youtu.be

Another video to confirm that Input Current (Iin on Ch2) can change from positive to negative value by varying the Input Voltage.

This means that we can vary the COP from 9.6mV to -16mV on Board 80 by increasing the Input Voltage Vrms from 360mV to 1.12V.  The sero Ch2 Vavg occurred when the Input CH1Vrms was at around 440mV.

The experiment can be repeated easily.  Board 80 can be guaranteed to be OU!!!

So now you know the "resonant" voltage needed for that particular circuit to produce a high reactive current. ?

Next ..... put a 1000 Uf capacitor (or more) in parallel with the DC supply, connected as closely as possible to the board, allow the capacitor to fully charge to the running voltage value, then disconnect the DC supply. Time how long it takes to discharge, or not!

Then, it's either TAaa DAAaaaaaaaa .... look at the "majick" we have here!,  or,  cheese, please, with my humble pie, thank you.

Good luck, whichever way it goes.

Cheers

[ltseung888]

@Lawrence: Congratulations on the measurement of COP vs. Input Voltage. That is an important bit of information. Your graph does not present the data correctly, though.

In graphing data one generally puts the "independent variable" on the horizontal axis and the "dependent variables" on the vertical axes. The IV is what the researcher is controlling and the DVs are what the researcher is measuring. In this case the Voltage Input is the IV and the COP is the DV. You have plotted "trial number" on the horizontal axis and both Vin and COP on the vertical axis and so your graph is garbled.

You could re-do this graph. It would display only the single COP line. The horizontal axis would be the voltage levels, and the vertical axis the calculated COP. Then your graph would display the relationship between Vin and COP properly.

Graph redone.

[ltseung888]

So now you know the "resonant" voltage needed for that particular circuit to produce a high reactive current. ?

Next ..... put a 1000 Uf capacitor (or more) in parallel with the DC supply, connected as closely as possible to the board, allow the capacitor to fully charge to the running voltage value, then disconnect the DC supply. Time how long it takes to discharge, or not!

Then, it's either TAaa DAAaaaaaaaa .... look at the "majick" we have here!,  or,  cheese, please, with my humble pie, thank you.

Good luck, whichever way it goes.

Cheers

One step at a time.  We just want to demonstrate OU here.  Do not expect one jump and you can reach the top of Mount Everest.

Try the Lasersaber Joule Ringer circuit if you want.  Use the oscilloscope analysis technique on that Circuit.  You will have much better luck or chance of success than this simple JT circuit.