Is joule thief circuit gets overunity?

[hoptoad]

One step at a time.  We just want to demonstrate OU here.  Do not expect one jump and you can reach the top of Mount Everest.
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Then demonstrate it with something that provides corroborating data from a differing measurement set to your pretty scope shots. Corroborating data from alternative / adjunctive measurements is a great start to "demonstrating OU".

What better way to show OU than a simple capacitor test showing extended rundown periods or no rundown at all. Connect a capacitor,
do the test. It's that simple. You've already got everything there in your lab. It ain't rocket science. Surely you have a capacitor lying around somewhere?

Cheers

[ltseung888]

Then demonstrate it with something that provides corroborating data from a differing measurement set to your pretty scope shots. Corroborating data from alternative / adjunctive measurements is a great start to "demonstrating OU".

What better way to show OU than a simple capacitor test showing extended rundown periods or no rundown at all. Connect a capacitor,
do the test. It's that simple. You've already got everything there in your lab. It ain't rocket science. Surely you have a capacitor lying around somewhere?

Cheers

I am afraid that the experiments are not that simple.  With similar components, the FLEET boards could light up the LED for different length of time.  The average was 20 minutes.  But there were a few occasions that a Board lighted the LED for over four hours.  The longest I experienced was nine hours.  I never really understood why.   One possible explanation was "some kind of electromagnetic resonance".



The latest oscilloscope experiments suggested another possible explanation.   The Average Input Power could be positive – meaning energy was drained from the battery.  This would be the normal thinking.  But experiments also show that the Average Input Power could be negative – meaning energy was fed back to the Input Source.  That could recharge a battery or a capacitor.  This recharging happened at the same time as lighting up the LED.  Energy had to come from somewhere.  This was evidence for Lead-out Energy.



With the simple Joule Thief Circuit fluctuating around the "CH2 Vavg=0" position, positive COP and negative COP was clearly observed.  This meant alternative charging and draining.  This fluctuating condition was not that stable.  The hope was that this fluctuation could last forever and we could have achieved the Forever lighted Lamp with this simple circuit.  The reality was – the circuit now could not guarantee such occurrence.  The Lasersaber Joule Ringer circuit appeared to be much better but I have not tested it yet.



The next improvement I tried was to use a rechargeable battery in parallel with the capacitor.  Sure enough, we could detect that the rechargeable battery could go up in Voltage considerably (from 1.26V to 1.40V).  But it could also drop from 1.4V back to 1.26V or lower.  One manual procedure was to watch whether the battery was in the recharging or the draining state.  On recharging state, left it alone.  On draining state, took it out.  Let the battery rest and recharge another battery.  Obviously, such a process could only be possible in a research environment.



It appeared that many people at this forum did not have a DSO to observe what was really happening with the JT circuit and the variations.  They experimented using only multimeters.  It was like shooting birds in the dark.  They hoped to fire and  pick up some birds for dinner.  Lead-out Energy Technology is not that simple.  God  Bless.....

[poynt99]

Lawrence,

As I've discussed in the past, using two voltage meters (one across the battery and one across the battery CSR) will provide a very accurate Pin measurement. Simply set the two meters on DC volts (or millivolts) and multiply the average battery voltage by the average battery current (assuming a 1 Ohm CSR).

Don't try this for Pout though, as it will not provide a correct result.

[NickZ]

  The only proof that we are looking for is that you make a video of your BEST PROVEN OU BOARD, only. Charge a capacitor, and let it run down to nothing. That is all you need to do.
Oh, you already did that, and it drained, in a few minutes, not hours, and DIED. 
  WOW! 
           
   If you let the capacitor rest, the bounce-back effect will charge it back up, not your FLEET lead out, bring-in energy BS. If you further connect it back into the circuit, if will again drain to nothing. Period.
  The led bulb's load drain on the circuit is higher than what what the bounce back effect will provide, and there will always be a negative discharging voltage and current drain.  Regardless of what your scope is showing you. The proof is the dead capacitor, or battery, in EVERY SINGLE CASE.

  You should build the Lasersaber low draw circuit, or his Cross-over circuit, and test that on the capacitor. That is a much more economical circuit to use. Not the low perm iron powder toroid, with several resistors circuit, that you are now waisting your time on.

  The point being: That what you are doing is worthless, as there is no bright useable light coming out of your led(s). A blinking, dim led, is not what anyone is looking for a proof of OU.
  I would suggest that you STOP raving about what you have, or you will further discredit this forum.

   What you have done in trying to confirm OU is great. It's the idiotic raving, and religious BS that goes along with it that has most of us perplexed at your attitude.
All this while showing nothing, at all, that proofs anything close to, or resembling OU.
 

[ltseung888]

Lawrence,

As I've discussed in the past, using two voltage meters (one across the battery and one across the battery CSR) will provide a very accurate Pin measurement. Simply set the two meters on DC volts (or millivolts) and multiply the average battery voltage by the average battery current (assuming a 1 Ohm CSR).

Don't try this for Pout though, as it will not provide a correct result.

@Poynt99,

Sorry that I have to disagree with you on this point.  Please see the attached two diagrams showing the "voltmeter" readings and the Input CSR waveform.  The product of the two voltmeter readings cannot possibly give a correct Pin value.  We have to rely on the DSOs.

*** The "feedback or Back EMF" from the Circuit will modify the simple DC conditions at Input.

When will you show us your results from your 4-CH DSO?