Probality of God

[Qwert]

Here's something I find very interesting during an experiment with surface tension of water in micro-gravity.  Don Pettit suggests .......

Can you tell me? When Don Pettit suggests, you look very happy; when I suggest, you look not so happy: http://www.overunity.com/12716/probality-of-god/msg343769/#msg343769

[gravityblock]

The Centripetal Force of the earth moving around the sun is equal to the mass of the earth multiplied by earth's centripetal Acceleration.  The centripetal acceleration of the earth is Velocity² divided by orbit Radius = .00630446374625.  Therefore earth's centripetal Force is = 3.7651509559105 x 10²².  Thus, when you take the Pressure of the electrical-mass coming off the sun which is the pressure within the earth's energy sphere (.40276241457847) and multiply it by 1/3 of the surface area of the energy sphere (the amount of force that pushes the earth outwards), you get the exact same force that outer space is pushing back against the earth, which is the Centripetal Force of the earth = 3.7651509559105 x 10²²

Gravock

[gravityblock]

Below are the  7  equations which determine planet Density;


        1.  Density  =  orbit Radius  x  orbit Time  /  Surface Area of orbit Sphere

        2.  Density  =  orbit Radius  x  orbit Velocity  /  orbit Circumference

        3.  Density  =  Gravitational Acceleration  /  2 x orbit Acceleration

        4.  Density  =  Velocity of Light  /  2 x orbit Velocity

        5.  Density  =  √  Velocity of Light  /  4 Pi

        6.  Density  =  orbit Velocity  /  2 Pi

        7.  Density  =  orbit Radius  /  orbit Time


Gravity is absolutely "Pushing" us down onto the earth.  We upon the earth are exactly parallel to a Galilean Thermometer.  The force that we feel pushing us downwards is simply the result of the density of our bodies compared to the density of the ocean of electrical-mass that is surrounding the earth.  A simple difference in densities is what man defines as - Gravity.

Gravock

[hoptoad]

snip...
How can moving light from the sun reflect off the curved surface of the moon at all kinds of improper angles back into our eyes where we can see the entire circumference of the moon?  This isn't possible, because there is only one proper angle which light reflects off a curved surface (scientific evidence tells us this), such as the moon, thus the moon would only appear to us as a small dot.

If the moon were a perfectly smooth reflective surface, you might see only a small portion of the moon, but the moon has an uneven surface, composed of rock and dust which also has an uneven surface. Light is refracted and reflected at all angles, right across the whole surface of the moon that is exposed to that light.

snip...
  Now, If we assume light is stationary, and we're moving past stationary light via expansion acceleration (scientific evidence supports this), then it is possible for us to see the entire circumference of the moon, which is in-line with what we see and observe.
snip...

Now get two people standing 20 metres apart from each other, one with a torch pointing it at a ball that the other is holding.

If light were stationery, then how would the person shining the light at the ball, see the reflected light from that ball, when both persons are stationery with respect to each other. ? How would the person holding the ball see the light from the torch?    ??

[gravityblock]

The "gravity shadow" - why wouldn't there be a gravity shadow on the back side of the earth as an object crosses behind the earth from the sun side ?  It is not observed.

Gravock