Kapanadze Cousin - DALLY FREE ENERGY

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[NickZ]

  Yet another guess at the Akula circuit??? As this is NOT what he is showing on his video.
Has there been anyone that actually built his circuit, as he has it?  NO?

[ctbenergy]

hi magpwr,

1 layer coil with 40 turns (20 turns each), 1.5mm CW/CCW (red coil)
1 layer bifilar coil with 20 turns (10 turns each), 1.5mm CW/CCW (green/yellow coil)

2 coils center connected, red coil output shorted and ferrite core inside the pvc tube

.0001Ohm 

[Grumage]

hi magpwr,

1 layer coil with 40 turns (20 turns each), 1.5mm CW/CCW (red coil)
1 layer bifilar coil with 20 turns (10 turns each), 1.5mm CW/CCW (green/yellow coil)

2 coils center connected, red coil output shorted and ferrite core inside the pvc tube

.0001Ohm 

Dear ctbenergy and magpwr.

Although interesting, I wonder what the method of resistance measurement is employed by your Multimeters? I feel it would be quite different using the old fashioned Wheatstone bridge method!!

I have attached a formula for the calculation of resistance. The answer is based on a 1 Metre length of 2 mm Sq Copper wire.

If a frequency is involved with the measurement then all sorts of spurious values will be seen.

Dear magpwr. I have studied the link you posted earlier, (schematic attached). I don't understand why you have effectively shorted L2 & L3 together??

Cheers Grum.

[magpwr]

Dear ctbenergy and magpwr.

Although interesting, I wonder what the method of resistance measurement is employed by your Multimeters? I feel it would be quite different using the old fashioned Wheatstone bridge method!!

I have attached a formula for the calculation of resistance. The answer is based on a 1 Metre length of 2 mm Sq Copper wire.

If a frequency is involved with the measurement then all sorts of spurious values will be seen.

Dear magpwr. I have studied the link you posted earlier, (schematic attached). I don't understand why you have effectively shorted L2 & L3 together??

Cheers Grum.

hi Grumage,

Glad you dropped by.
I have constructed the SR193 device consisting of CW and CCW for the outer winding as i also wanted to emulate the experiment which was conducted in China using neon sign transformer but i had no proper caps yet.
Stripped  copper or aluminum tube not inserted yet for SR193.It's purely taking measurement like resistance and etc at this moment.

My discovery was based on measurement taken after CW and CCW was connected in series at the middle and my reading is taken from 2 points extreme left and right of the CW&CCW windings.
I just noticed the latest photo posted by ctbenergy which is similar to the winding in your schematic where 2 ends shorted together.This might have caused the confusion.I guess he was trying different variation consisting of CW & CCW.

CW & CCW winding in series on a pvc pipe does defy the laws of resistance if you connect multimeter probe either way.

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By the way have you seen this interesting experiment in JLN Lab.
GEGENE v1.1-Close loop test on induction heater with pancake coil

http://jnaudin.free.fr/gegene/gegene13en.htm

That experiment was on the verge of success the shortfall was that he was using mere 500watt "grid tie inverter"(This is important) .Base on my calculation he would need inverter rating 750w+500w=1250watt  just to break even.2000watt 220volts grid tie inverter is impossible to find in ebay.Unless i combine 2 x 1000w grid tie inverter which isn't great although it would work(space constraint).
I will be conducting this experiment as well since i love to plan many experiments in my head and execute accordingly.
I have just purchased a set of capacitors consisting of100,000uf x 3 40vdc for the above experiment from ebay.I was unable to spot any other 100,000UF caps 40VDC at least which is able to be shipped outside of USA in ebay.

It makes sense why the creator mentioned he is only getting 250watt to go into the inverter.
The fast diode "HFA25PB60" 25Amp used is underrated big time.

Say 15volts input base on example x 25Amp =375watt power would ever reach the inverter.Not forgetting the voltage drop and heat factor in the diode.
Solution-
If he were to use 100Amp for each diode or (25Amp x 4 for each existing diode) with same 15volts .The maximum power to the inverter would be 100Amp x 15volts=1500watt.
At this point it would be a close loop device for sure.