Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[Doug1]

Hannon
You will also have to add to the calculation how much effect  one set of electromagnets helps to collaps the other set or pushes the feild in the other direction as the one set is powering up the other is powering down not just to a state of off but being pushed by the other harder then it would fall by itself. The back emf will be aided by the forward emf of the other.

[hanon]

Hi all,

In the attached Excel file there is a calculation to obtain the two 90º unphased signals required in the 1908 patent. The method is very simple, and is summarized as follows:

            1- From a AC signal apply a full wave rectification to convert it into two always positive waves. ( By using a center tapped rectifier you can obtain two series of signals: one coming from the positive half waves of the AC signal, and the other signal from the negative half waves of the initial AC signal ). Also you can create both series using a PWM, taking a derivation of its output to a NOT gate, and then two transistors to create two independient square signals.

            2- Apply a RL filter or a RC filter. This filter will smooth and will create a lag in order that both series of signals will be delayed and, thus, superimposing themselves. This way you can obtain the two unphased signals.

The RL filtering of RC filtering is defined by the value of L/R or R·C in each case. Choosing a proper value you can get the required result. All the info is included into the Excel file. I have included both possibilities because I don´t know if you can use a RC filter with high amperages, or if the output intensity will rever its direction in an RC circuit. Please comment.

Regards

[Doug1]

 Its obvious no one has figured this out yet or come up suporting evidence in a working operational theory. I think the patent was skillfully executed. 

 

[RMatt]

Hi all, Bob here with a thought or 2?

IMHO,

In PJ Kelley's newest ebook V24.01 R. Date 14 AUG 13, pg 175, next to the bottom of the page,

"Señor Figueras has constructed a rough apparatus
by which, in spite of it's small size and it's defects, he obtains 550 volts, which he utilises in his own house for
lighting purposes and for driving a 20 horse-power motor."

1. 1 HP = 746 wats, 20hp = 14,920W, + lights (lets say 80W), TOTAL=15,000 Watts

2. 15,000 Watts/ 550 Volts = 27.27 AMPS (lot of Amps) Maybe multi stage trans. to get it to useful?

3. 7 sets would be 27.27 Amps each with a Voltage of approx. 78.6 Volts

4. So if there were 27.27 AMPS in each set, and each set had 78.6 Volts, with 7 sets there would be:: 15,004 WATTS.

5. If there were 10 sets, each would have 27.27 AMPS and about 78.6 VOLTS, with 10 sets there would be 21,432 WATTS.

Comments welcome and needed as alsways

Bob

(It's funny what my little brain thinks of when I have a drink or two! LOL)

[RMatt]

Hi all again,

I think I might need another drink or three to get this straight.