Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[marathonman]

I see you're stupidity is leaking out again seaad. if you actually study the device in depth you will realize everything i post is facts backed by Physics. i do not have to lower myself to really stupid childish remarks such as you have.
If you have nothing to add but BS then please either shut your smart A$$ mouth or stay away as either will suffice.

the Figuera device does NOT sidestep the Lenz Law in any way shape or form.

ayeaye;
What is your question and what don't you understand. i have posted a lot of information in the past posts that were really informative. please let me know.

Marathonman

[ayeaye]

What is your question and what don't you understand. i have posted a lot of information in the past posts that were really informative. please let me know.

I don't know, all i see about the device, is a pdf file, where i cannot see horns or tails. So also no way can i see how this supposed to overcome the Lenz law. I didn't say eliminate the Lenz law, but overcome the implications of it, that cause unity. There could be some better diagrams of the device and better explanation, so it can be seen what it actually is. I'm of course not into it at all, so there are sure things that i don't know by now, but so are many others i think.

I wonder how it can be done, the symmetry of induction is so overwhelming, just whatever you do, the symmetry remains.

Can it be simulated somehow, with spice or whatever?

Ok, it is something like on the figure below, i guess. Now what it looks like, moving the potentiometer in whatever direction, the Lenz effects on both primary coils are in the same direction, which induces current in the secondary coil in one direction. At that, the Lenz effect of one of the primaries is caused by increasing current, thus the power is positive, and the Lenz effect of the other primary is caused by decreasing current, thus the power is negative (generated by the coil). Now the question is, is the power generated by the second primary greater than the power consumed by the first primary, or not. In that case the Lenz effect is still against the current in the first primary, while it is in the same direction in the second primary. Of course coils generate power when the current decreases, but consume power when it increases, and both are there, i don't see that the Lenz effect is anyhow overcome in that circuit. That's just as i see, i don't say it's one way or other way. But i don't see any reason for overunity in that circuit, or i overlooked something.

Ok, unless the Lenz effect in the first primary may somehow additionally delay the current reaching zero in the second primary. I don't know, didn't think about it, but things like that i think cannot be found out by simulation.

[seaad]

ayeaye
Example sim. and tests not the best.

https://overunity.com/12794/re-inventing-the-wheel-part1-clemente_figuera-the-infinite-energy-machine/msg526148/#msg526148

Regards

[ayeaye]

This? Measure the input and output power of it too, the same way as i did there  https://overunity.com/17861/bifilar-pancake-coil-overunity-experiment/ . Without it, such experiments make no sense whatsoever. Measure it on real circuit that is, not in the simulator, for very theoretical reason the simulator there cannot model overunity.

[marathonman]

The magnetic fields of the primaries will always be opposing as the Lenz effect will always keep them opposing whether they are increasing or decreasing to maintain the pressure between them. by raising one primary and lowering the other the Electric fields are alligned  as such to be positive and additive  thus presenting the secondary a magnetic field with the same intensity as a north south field of a standard generator.

As i have stated when half of the device is reduced it will release that reduced  potential into the system to offset the potential drop of the rising side of the devi e. The reducing side will always counteract the increasing sides potential drop minus losses ocurred  withe the secondary feed back to replace the losses and give rise to amplification to the rising primaries to maintain the needed pressure for your output.

When i get to a computer i can explain further as i am on my phone and can barely  see the screen..

Regards,

Marathonman