Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[bajac]

RMatt,
Thank you for the information! I have found it very interesting so far. I will keep reading it.


Farmhand,
I prefer to conduct new tests using the 1908 configuration and re-evaluate the results. I just do not see the point for arguing on results from tests that do not really replicate Figuera's settings. Let's just wait a few more weeks when I expect to have completed the driving circuit. Anyway, we have waited for more than 100 years.

[Farmhand]

Then this is for the others who may be interested.

OK then, so lets just suppose the DC resistance of the coil is an arbitrary 5 Ohms and the current is 0.463 Amperes.  Power = Current squared x Resistance or P= (I x I) x R. So assuming that the reactance portion of the impedance does not dissipate power we get the result below.

I = 0.463 Amperes and R = 5 Ohms so 0.463 x 0.463 = 0.214369 x 5 = 1.07 Watts dissipated in the example above.

So now lets say the input for the above example is 9.2 Watts, then if we divide the 1.07 W x 9.2 W = 0.11 % of the input is dissipated in the 5 Ohms DC resistance of the coil.

No point to working out a C.O.P. as there is no output. But if it were expressed as a C.O.P. it would be a C.O.P. = 0.11. I think.

Not knowing any actual resistances I'll leave it at that.

I think it is very important that other people do not get the wrong idea and go shouting C.O.P. 3 which whips up hype.

So the only thing left is for other people to either do the math themselves or get another opinion before they go shouting C.O.P. 3.

I think there is sufficient evidence in the links I provided to suggest the method I employed is correct.

Cheers

P.S. The Thevenin Theorem allow us to ascertain the output impedance and so with that we can calculate the power which would be delivered to a given load.

Maybe someone will confirm or correct my calculation.

..

[bajac]

FYI: in practice things are more complicated.


On a regular basis, I have to witness factory tests and I also have to review the test reports for traction power transformers and rectifier equipment. In these reports, you cannot take for granted the DC resistance of the coils. For example, because the DC resistance changes with temperature we have to use formulas to extrapolate between the DC resistance and the actual temperature of the winding.

[Farmhand]

FYI: in practice things are more complicated.


On a regular basis, I have to witness factory tests and I also have to review the test reports for traction power transformers and rectifier equipment. In these reports, you cannot take for granted the DC resistance of the coils. For example, because the DC resistance changes with temperature we have to use formulas to extrapolate between the DC resistance and the actual temperature of the winding.

I didn't take it for granted I asked you but you didn't say so I used an arbitrary figure as an example. As I stated clearly.

The point is only the DC resistance dissipates power. The AC reactance impedance does not.

..

[Doug1]

Are we assuming the device in question was producing ac? After looking over the news paper articles I see no evidence which would indicate the currents are alternating or direct. Motors and lights come in both forms ac and dc.
  Many days of deeper reading have brought me to a place where I have some concerns over the assumptions that this device is producing ac currents.Not to say it could not be used by conversion into ac. Just something to think about.
  As for That-Prophet, not only can one make the loop.It can run with gain. 100 watts can become 10,000 as was proven in WWII on most battle ships.It's called an Amplidyne.