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Overunity Machines Forum



Reactive power - Reactive Generator research from GotoLuc - discussion thread

Started by hartiberlin, December 12, 2013, 04:34:12 PM

Previous topic - Next topic

0 Members and 6 Guests are viewing this topic.

tinman

Quote from: poynt99 on December 31, 2013, 10:10:58 AM
In the mean time Luc, I've taken the time to make this pretty little diagram for you.

Someone presents you with the following physical circuit and diagram, and asks you to use the DVM to measure the voltage across the 4 components; 3 resistors and one battery.

Would you please indulge me, take two minutes to reply and tell me what color lead from the DVM you would use for each test point (TP) for each component, starting from the left at R1 as follows (R=Red=+, B=Black=-):

R1
TP1: R or B?
TP2: R or B

R2
TP2: R or B?
TP3: R or B

B1
TP3: R or B?
TP4: R or B

R3
TP4: R or B?
TP5: R or B
Now that Luc has answered,i would like a go,as some times what seems simple ,is often not how it is.
As you show a battery,we can asume DC.
So R1-TP 1 or TP 5 black,TP 2 red.
R2 -TP 2 black-TP3 red
R3-TP4 black-TP 5 or TP 1 red.
B1-TP 3 red-TP 4 black.

gotoluc

Quote from: tinman on December 31, 2013, 10:38:33 AM
Interesting power configuration you have over there. We have our 240 single phase,450 single phase,and 450 3 phase.

I will try and make your reactive circuit,but although i have many MOT's,im limited on cap's-but we will see what we can do. But my point with this will be to show you that the power is already stored within your generator,and a load is already present within the generator-even without your reactive circuit turned on.

The one thing that must be remembered is that in order to create the reactive power,we must first have active or real power. Without it,we have nothing.

Humm... why are you mentioning a MOT when I have written many pages back it's not needed and also have made the 2 new tutorial to demonstrate the effect without any MOT?

Keep in mind that a generator with an exciter rotor field (like I'm using) uses a capacitor to build the electromagnetic field in the rotor. Without that capacitor you have no rotating magnet = no voltage or current.

To conclude the power I getting out of the Alternator is coming from the  exciter rotor field capacitor would it not be like saying we will remove permanent magnets out of a PM Alternator since that's where you're getting your power from.

Luc

gotoluc

Quote from: tinman on December 31, 2013, 10:45:34 AM
Now that Luc has answered,i would like a go,as some times what seems simple ,is often not how it is.
As you show a battery,we can asume DC.
So R1-TP 1 or TP 5 black,TP 2 red.
R2 -TP 2 black-TP3 red
R3-TP4 black-TP 5 or TP 1 red.
B1-TP 3 red-TP 4 black.

I would agree with TinMan if we wanted to know the "Polarity" of the components. Was that your question poynt?   and wrote Voltage instead?

Luc

tinman

Quote from: gotoluc on December 31, 2013, 11:10:02 AM
Humm... why are you mentioning a MOT when I have written many pages back it's not needed and also have made the 2 new tutorial to demonstrate the effect without any MOT?

Keep in mind that a generator with an exciter rotor field (like I'm using) uses a capacitor to build the electromagnetic field in the rotor. Without that capacitor you have no rotating magnet = no voltage or current.

To conclude the power I getting out of the Alternator is coming from the  exciter rotor field capacitor would it not be like saying we will remove permanent magnets out of a PM Alternator since that's where you're getting your power from.

Luc
Because im building your original setup to explain your question Quote:So if you think a power generating station generators will see an extra load if I power my load at a power factor of zero can you or Farmhand then explain why when I connect the same load to my Generator (mini power generating station) the generators does NOT see an extra load.

I am also going to show you that a far greater load can be pulled from the generator ,than that that was drawn by your reactive circuit-without any extra load being placed on the prime mover.
You asked the question Luc,so im going to answer it-with a working device.

But basically what you are doing,is taking some of the power from the exciter circuit to run your reactive circuit.What your reactive circuit disipate's is equal to the power lost in the exciter(tank)circuit of the generator.This is why you see no extra load on your prime mover-you have tuned your reactive circuit to the exciter tank circuit-every action has an opposite and equal reaction.

tinman

Also-a happy new year to you all.
Us Aussies are already in the year 2014,but i know the other half of the world is yet to catch up lol.