The Holographic Universe and Pi = 4 in Kinematics!

[TinselKoala]

You did not show where you got your numbers from.  The tangential velocity in your post is not based on empirical data or a real physical measurement.  How did you calculate the tangential velocity?  Please provide the equation you used for this.

Gravock

Having trouble reading? Here, I'll quote the post again. Note what it says in the first few sentences.  If you try very hard I'll bet you might be able to follow through the math.
I see that reference frames also confuse you. Hint: There is a reference frame in which the orbit of the Earth about the sun is not a helix, but rather is a closed ellipse of very low eccentricity.

Earth's orbital radius = about 149.6 million km. Duration of one full orbit is of course one sidereal year, 365.256 days or about 31,558,118 seconds.
(wikipedia).

The tangential velocity of the Earth in its orbit is 29814 meters per second, derived from v²=GMs/r. (That is, from PHYSICAL MEASUREMENTS.)

Now let us calculate.

(EVERYTHING AFTER THIS POINT IS CALCULATION AS SHOWN, WITH UNITS INCLUDED.)

The circumference of the orbit (assuming pi = 3.1416 and a circular orbit) is 2 x pi x 149.6 million km, or about 939.97 million km.

The tangential speed computed from the radius and the conventional value of pi is therefore 939.97 million km / 31,558,118 seconds or about 29785 meters/second.

The diameter of the orbit is about 299.2 million km. Traversing this distance at the tangential velocity of 29814 m/sec will therefore take about 10035553 seconds. Four times that is 40,142,212 seconds... but a year is only 31,558,118 seconds.  Curiously.... 10035553 x  3.1416 = about 31,527,693 seconds.... nearly exactly the number of seconds in a sidereal year.

Conclusion.....  The value of pi, for the real figure of the Earth's orbit, taking TIME and velocity into account, must be very close to 3.1416, and not close at all to 4.

Please feel free to show a working that demonstrates otherwise.

Please feel free to SHOW A WORKING that demonstrates otherwise. Be sure to include your units, and try to avoid fake precision.

[gravityblock]

Earth's orbital radius = about 149.6 million km. Duration of one full orbit is of course one sidereal year, 365.256 days or about 31,558,118 seconds.
(wikipedia).

The tangential velocity of the Earth in its orbit is 29814 meters per second, derived from v²=GMs/r.

Now let us calculate.
The circumference of the orbit (assuming pi = 3.1416 and a circular orbit) is 2 x pi x 149.6 million km, or about 939.97 million km.

The tangential speed computed from the radius and the conventional value of pi is therefore 939.97 million km / 31,558,118 seconds or about 29785 meters/second.

The diameter of the orbit is about 299.2 million km. Traversing this distance at the tangential velocity of 29814 m/sec will therefore take about 10035553 seconds. Four times that is 40,142,212 seconds... but a year is only 31,558,118 seconds.  Curiously.... 10035553 x  3.1416 = about 31,527,693 seconds.... nearly exactly the number of seconds in a sidereal year.

Conclusion.....  The value of pi, for the real figure of the Earth's orbit, taking TIME and velocity into account, must be very close to 3.1416, and not close at all to 4.

Please feel free to show a working that demonstrates otherwise.

@ All,

I do not agree with the calculations and the values used by TK.  Now, pay close attention.  Pi = 4 is the ratio between the Distance + Time of the circumference and the diameter.  However, Pi = 3.14 is the ratio between only the distance of the circumference and the diameter.  Below is the mathematical proof and it is based on Frank Znidarsic's quantum transitional speed of 1.0939 MHz meters or 1,094,000 m/s.  We'll use the values in which TK has provided.  Then we'll reconcile the differences between his values and the values in which I accept in a later post, assuming of course he concedes from his current positon.

According to TK's values, the diameter of the orbit is about 299.2 million km. Traversing this distance at the tangential velocity of 29814 m/sec will therefore take about 10035553 seconds. Four times that is 40,142,212 seconds... but a year is only 31,558,118 seconds.  Curiously.... 10035553 x  3.1416 = about 31,527,693 seconds.... nearly exactly the number of seconds in a sidereal year.

4 * 10035553 seconds = 40,142,212 seconds, and 3.1416 * 10035553 seconds = 31,527,693 seconds

40,142,212 seconds / 31,527,693 seconds = 1.27200906 or 4 / 3.14 = 1.27...
4 - 3.14 = 0.86
1.27200906 * 0.86 = 1.093927791, which is equal to the quantum transitional speed of 1.094 MHz meters or 1,094,000 m/s.  The quantum transitional speed is directly tied to the Planck's constant, the fine structure constant, the speed of light, the speed of sound in the nuclear structure of the atom, etc.

The taxicab geometry is showing the distance + the Time of the circumference is 4 times longer than the distance + the Time of the diameter.  MarkE is trying to eliminate "Time" by connecting the inner square vertices with chords in the squaring method of the taxicab geometry in order to get the conventional Pi of 3.14, which is the ratio of the distance only.  By doing so, then he his left with only the distance of the circumference without Time.  Space-Time is inseparable, and it is a shame how plane geometry in it's current form conveniently leaves Time out of the mathematical equation.  This is proof that Time is real and is more than a man made concept used solely for the purpose of measurement.

Gravock

[gravityblock]

Zzzzzzzz.

It appears from my last post that you have some waking up to do.  You need to get true to yourself.

Gravock

[gravityblock]

@ All,

I do not agree with the calculations and the values used by TK.  Now, pay close attention.  Pi = 4 is the ratio between the Distance + Time of the circumference and the diameter.  However, Pi = 3.14 is the ratio between only the distance of the circumference and the diameter.  Below is the mathematical proof and it is based on Frank Znidarsic's quantum transitional speed of 1.0939 MHz meters or 1,094,000 m/s.  We'll use the values in which TK has provided.  Then we'll reconcile the differences between his values and the values in which I accept in a later post, assuming of course he concedes from his current positon.

According to TK's values, the diameter of the orbit is about 299.2 million km. Traversing this distance at the tangential velocity of 29814 m/sec will therefore take about 10035553 seconds. Four times that is 40,142,212 seconds... but a year is only 31,558,118 seconds.  Curiously.... 10035553 x  3.1416 = about 31,527,693 seconds.... nearly exactly the number of seconds in a sidereal year.

4 * 10035553 seconds = 40,142,212 seconds, and 3.1416 * 10035553 seconds = 31,527,693 seconds

40,142,212 seconds / 31,527,693 seconds = 1.27200906 or 4 / 3.14 = 1.27...
4 - 3.14 = 0.86
1.27200906 * 0.86 = 1.093927791, which is equal to the quantum transitional speed of 1.094 MHz meters or 1,094,000 m/s.  The quantum transitional speed is directly tied to the Planck's constant, the fine structure constant, the speed of light, the speed of sound in the nuclear structure of the atom, etc.

The taxicab geometry is showing the distance + the Time of the circumference is 4 times longer than the distance + the Time of the diameter.  MarkE is trying to eliminate "Time" by connecting the inner square vertices with chords in the squaring method of the taxicab geometry in order to get the conventional Pi of 3.14, which is the ratio of the distance only.  By doing so, then he his left with only the distance of the circumference without Time.  Space-Time is inseparable, and it is a shame how plane geometry in it's current form conveniently leaves Time out of the mathematical equation.  This is proof that Time is real and is more than a man made concept used solely for the purpose of measurement.

Gravock

Wheeler clearly pointed out that matter and space continually interact. Quoting Wheeler: "Space acts on matter, telling it how to move. In turn, matter reacts back on space, telling it how to curve."

Pi = 4 for the ratio between the Distance + the Time of the circumference and the diameter, clearly reflects Wheeler's quote on how matter and space continually interact.

Gravock

[MarkE]

@ All,

I do not agree with the calculations and the values used by TK.  Now, pay close attention.  Pi = 4 is the ratio between the Distance + Time of the circumference and the diameter. ...

Gravock

LOL.  Other than the established crackpot Miles Mathis there are few who would continue to fight your many times lost battle with reality.