Overunity electrolysis - 31 times more effective gas production than with DC

[ltseung888]

 

Lawrence,
I would like to offer a slightly different angle on your conjecture, one that relates to your lead-out work with the Joule Theif. I recall you posting about your team having put a secondary on the JT and then using the secondary's configuration to produce a feedback dynamic resulting in a standing wave, which can be drawn upon to produce excess energy. I believe this is the basic principle that has been spoken of by at least one person who was present at Stan Meyer's disclosure of his method to the Maori people in New Zealand.

Some commentators like Bearden will state that the inductive kickback is actually the aether pushing back on the circuit with energy from the vacuum to restore balance from the unbalanced state produced by a voltage spike. My question is:

Does this energy from the vacuum have some kind of unique property which orders water to be more perfectly aligned (at the intra and inter-molecular level) in order that it can produce gases in overabundant quantity as Meyer and others who follow his method have claimed?

It is one thing to pulse water with a high voltage spike. But it seems to be quite another to take the inductive kickback from a circuit to produce a standing wave, and then, to use the standing wave's claimed overunity to drive a water-fracturing circuit. Does the energy from the vacuum in fact constitute a more primeval and effective ordering force for water to properly align for this kind of superabundant gas production to take place?

Here are some of the posts where you dealt with a standing wave in the JT produced by secondary configuration. See this post and subsequent posts further down on page:
[/font]http://www.energeticforum.com/renewable-energy/7434-lee-tseung-lead-out-bring-energy-theory-4.html#post136798

Bob

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@Bob,
When I returned to Hong Kong from USA two years ago, I got support.  We gave over 150 free samples.  I believe overunity.com, energetic forum and overunityresearch.com moderators got them also.
One important component is the Super Capacitor – 10F.  After the battery was removed, the LEDs continue to light for over 20 minutes.  In some cases, the LEDs blinked and lighted for over 10 hours.
Geoffrey Sun discovered a strange behavior.  Some Boards have the LEDs off and then on brightly again.
See:
https://www.youtube.com/watch?v=RB3sSus1-B4&list=UUCzf8o1PPM8ozwNgWyk5lHw&index=12
Some groups started to work on varying the inductance and the capacitance and the Stan Meyer Water Fuel Cell type experiments.  At least one group showed promising results and got funded.  (All information became confidential as to be expected.)
I am reproducing some slides on my thoughts.  (Thoughts only – no experimental confirmation yet.)
Lawrence

[Void]

When I returned to Hong Kong from USA two years ago, I got support.  We gave over 150 free samples.  I believe overunity.com, energetic forum and overunityresearch.com moderators got them also.
One important component is the Super Capacitor – 10F.  After the battery was removed, the LEDs continue to light for over 20 minutes. 

Hello ltseung888 my friend. Hope you are doing well.
It should be expected that a 10F super capacitor can run a Joule Thief circuit for 20 minutes or more
after being charged for only 10 seconds with an AA battery (approx. 1.5V). Exact results will depend
on the type of AA battery that is used to charge the 10F super capacitor, but I did a quick test using
my bench power supply set to 1.5VDC (max 3 Amps current), and I was able to charge a 10F super capacitor fully to 1.5V
after 10 seconds of charging.
Here are the calculations:
A 10F capacitor at 1.5V = 11.25 Joules of stored energy
20 minutes run time of the Joule Thief circuit  = 20 mins x 60s/min = 1200 seconds
1 Watt = 1 Joule/second so, 
11.25J /1200s = 9.38 mW average power consumption over the 20 minute period.
Since a Joule thief's power consumption falls off as the supply voltage falls, and a joule thief
only consumes maybe about 10mW to 5mW max or so in the voltage range of 1.5V to 0.4V supply voltage,
then it is an expected result that the 10F capacitor can run the joule thief circuit for at least 20 minutes
when charged to around 1.5V. This appears to be quite normal behavior.
All the best...

[ltseung888]

Hello ltseung888 my friend. Hope you are doing well.
It should be expected that a 10F super capacitor can run a Joule Thief circuit for 20 minutes or more
after being charged for only 10 seconds with an AA battery (approx. 1.5V). Exact results will depend
on the type of AA battery that is used to charge the 10F super capacitor, but I did a quick test using
my bench power supply set to 1.5VDC (max 3 Amps current), and I was able to charge a 10F super capacitor fully to 1.5V
after 10 seconds of charging.
Here are the calculations:
A 10F capacitor at 1.5V = 11.25 Joules of stored energy
20 minutes run time of the Joule Thief circuit  = 20 mins x 60s/min = 1200 seconds
1 Watt = 1 Joule/second so, 
11.25J /1200s = 9.38 mW average power consumption over the 20 minute period.
Since a Joule thief's power consumption falls off as the supply voltage falls, and a joule thief
only consumes maybe about 10mW to 5mW max or so in the voltage range of 1.5V to 0.4V supply voltage,
then it is an expected result that the 10F capacitor can run the joule thief circuit for at least 20 minutes
when charged to around 1.5V. This appears to be quite normal behavior.
All the best...

@void,
Thanks for the estimation.  The direction I took was - what makes something a super capacitor?  Can I assume that the "electron cloud" distribution is responsible?
If so, electric field applied to water dipoles should be able to change the "electron clouds".  Different electron clouds can be stable and contain different energy.
Lead-out energy then becomes a matter of using such energy.
Divine Revelation?
God Bless,
Lawrence

[Void]

@void,
Thanks for the estimation.  The direction I took was - what makes something a super capacitor?  Can I assume that the "electron cloud" distribution is responsible?
If so, electric field applied to water dipoles should be able to change the "electron clouds".  Different electron clouds can be stable and contain different energy.
Lead-out energy then becomes a matter of using such energy.
Divine Revelation?
God Bless,
Lawrence

Hello Lawrence. The thing to consider is, does a super capacitor at 10 Farads provide more
run time (more energy storage/energy delivery) for a device such as a joule thief than if we take a bunch of
regular electrolytic or other type capacitors and parallel them together to make 10 Farads total? There
is no reason to think there would be any difference. 10 Farads is 10 Farads, so the result should be the same.
A 10 Farad capacitor at 1.5V charge will power a joule thief circuit for about 20 minutes at least, whether you are
using a super capacitor or whether you are using a bank of capacitors made from other type capacitors. Whether you
are using a super capacitor or not should not make any difference.  In that sense there should be nothing special
about a super capacitor except that they have a larger capacitance in a much smaller package than other
types of capacitors. They are able to store more charge in a smaller package, but for a given capacitance
the amount of energy storage is the same as with capacitors of another type of the same capacitance.
Anyway, I just wanted to point out that there is nothing unusual about running a joule ringer circuit for twenty minutes
using a 10F capacitor charged to about 1.5V. That is a normal and expected result.
All the best...

[ltseung888]

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Principle construction of a supercapacitor; 1. power source, 2. collector, 3.polarized electrode, 4. Helmholtz double layer, 5. electrolyte having positive and negative ions, 6. Separator.  See diagram.

Electrochemical capacitors (supercapacitors) consist of two electrodes separated by an ion permeable membrane (separator), and an electrolyte connecting electrically the both electrodes. By applying a voltage to the capacitor an electric double layer at both electrodes is formed, which has a positive or negative layer of ions deposited in a mirror image on the opposite electrode.
Source: http://en.wikipedia.org/wiki/Supercapacitor

***** supercapacitor itself has elements of electrolysis.  Can "ordered water" store electrical energy in similar fashion?
If it all boils down to the electron cloud arrangements, such may be possible.  Such research has scientific backing.